All categories

3 years ago

Which is true about light and heat?

Physics

2 answers:

Snowcat [4.5K]3 years ago

5 0

My best guess is c) Dark colors reflect less radiation making them warmer.

hope this helps!

VikaD [51]3 years ago

3 0

Dark colors reflect less radiation making them warmer.

~APEX

You might be interested in

Calculate the angle for the third-order maximum of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.

alekssr [168]

Answer: The angle of diffraction is 0.498°

Explanation:

To calculate the angle of diffraction, we use the equation given by Bragg, which is:

$n\lambda =2d\sin \theta$

where,

n = order of diffraction = 3

$\lambda$ = wavelength of the light = $580nm=5.80\times 10^{-7}m$ (Conversion factor: $1m=10^{9}nm$ )

d = spacing between the crystal planes = 0.100 mm = $1.0\times 10^{-4}$ (Conversion factor: 1 m = 1000 mm)

$\theta$ = angle of diffraction = ?

Putting values in above equation:

$3\times 5.80\times 10^{-7}=2\times 1.00\times 10^{-4}\sin \theta\\\\\sin \theta = 0.0087\\\\\theta=\sin ^{-1} (0.0087)=0.498$

Hence, the angle of diffraction is 0.498°

6 0

3 years ago

A metal rod of length (L) moves with velocity (v), perpendicular to its length, in a magnetic field B, which is perpendicular to

Alborosie

Explanation:

If a metal rod of length L moves with velocity v is moving perpendicular to its length, in a magnetic field B, the induced emf is given by :

$\epsilon=Blv$

The electric field in the conductor is given by :

$E=\dfrac{\epsilon}{l}\\\\E=\dfrac{Blv}{l}\\\\E=Bv$

It is clear that the electric field is independent of the length of the rod. If the length of the rod is doubled, the electric field in the rod remains the same.

6 0

3 years ago

How to find the total displacement of an object ?

OLga [1]

Answer:

it can be calculated by measuring the final distance away from a point, and then subtracting the initial distance

8 0

3 years ago

A thin layer of oil of refractive index 1.22 is spread on the surface of water (n = 1.33), If the thickness of the oil is 275 nm

ANTONII [103]

Answer:

6.71×10⁻⁷ m

Explanation:

Using thin film constructive interference formula as:

2×n×t = m×λ

Where,

n is the refractive index of the refracted surface

t is the thickness of the surface

λ is the wavelength

If m =1

Then,

2×n×t = λ

Given that refractive index pf the oil is 1.22

Thickness of the oil = 275 nm

Also, 1 nm = 10⁻⁹ m

Thickness = 275×10⁻⁹ m

So,

Wavelength is :

λ= 2×n×t = 2× 1.22 × 275×10⁻⁹ m = 6.71×10⁻⁷ m

8 0

3 years ago

two pendulums of lengths 100cm and 110.25cm start oscillating in phase. after how many oscillations will they again be in same p

goldfiish [28.3K]

Angular frequency of pendulum is given by

$\omega = \sqrt{\frac{g}{l}}$

for both pendulum we have

$\omega_1 = \sqrt{\frac{9.81}{1.00}}$

$\omega_1 = 3.13 rad/s$

For other pendulum

$\omega_2 = \sqrt{\frac{9.81}{1.1025}}$

$\omega_2 = 2.98 rad/s$

now we have relate angular frequency given as

[tex\omega_1 - \omega_2 = 3.13 - 2.98 = 0.15 rad/s[/tex]

now time taken to become in phase again is given as

$t = \frac{2\pi}{\omega_1 - \omega_2}$

$t = \frac{2\pi}{0.15} = 41.88 s$

now number of oscillations complete in above time

$N = \frac{t}{\frac{2\pi}{\omega_1}}$

$N = \frac{41.88}{\frac{2\pi}{3.13}}$

$N = 21 oscillation$

3 0

3 years ago