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2 years ago

The collective body of observations of a natural phenomenon on which scientific explanations are based is called?

Physics

2 answers:

zhenek [66]2 years ago

4 0

Experimental Evidence.

Scientists conduct experiments or observations to gather evidence that either support or disprove a given hypothesis. Hence, all the scientific explanations are based on this body of observations.

Greeley [361]2 years ago

3 0

The collective body of observations of a natural phenomenon on which scientific explanations are based is called emphirical evidence.

<u>Explanation:</u>

The information and data received through observations and experience by performing various kinds of experiments to conclude and predict the pattern of a phenomeno with the help of science to explain its behaviour is called empirical or experimental evidence.

This is helpful for the researchers and developers as it gives further insights about the phenomeno and paves way for them to proceed or to further conduct experiments resulting in some conclusions.

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The greater the mass of an object

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Answer:

The greater the velocity, the greater the Force needs to be, and the greater the fiction is

Explanation:

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3 years ago

The latent heat of vaporization of a substance is the amount of energy associated with doing which of the following to 1 kg of t

mr Goodwill [35]

Converting it from liquid to gas

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3 years ago

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A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches

tiny-mole [99]

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

x = distance

t = time

a = acceleration

${v}^{2} = {z}^{2} + 2ax$

$v = z + at$

First let's find the final velocity the plane will have at the end of the runway using the first equation:

${v}^{2} = {0}^{2} + 2(5)(1800)$

$v = 60 \sqrt{5}$

Now we can plug this into the second equation to find t:

$60 \sqrt{5} = 0 + 5t$

$t = 12 \sqrt{5}$

Then using 3 significant figures we round to 26.8 seconds

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2 years ago

You are removing branches from your roof after a big storm. You throw a branch horizontally from your roof, which is a height 3.

mart [117]

Answer:

The initial velocity in the x-direction with which the branch was thrown is approximately 10.224 m/s

Explanation:

The given parameters of the motion of the branch are;

The height from which the branch is thrown = 3.00 m

The horizontal distance the branch lands from where it was thrown, x = 8.00 m

The direction in which the branch is thrown = Horizontally

Therefore, the initial vertical velocity of the branch, $u_y$ = 0 m/s

The time it takes an object in free fall (zero initial downward vertical velocity) to reach the ground is given as follows;

s = $u_y$ ·t + 1/2·g·t²

Where;

$u_y$ = 0 m/s

s = The initial height of the object = 3.00 m

g = The acceleration due to gravity = 9.8 m/s²

∴ s = 0·t + 1/2·g·t² = 0 × t + 1/2·g·t² = 1/2·g·t²

t = √(2·s/g) = √(2 × 3/9.8) = (√30)/7 ≈ 0.78246

The horizontal distance covered before the branch touches the ground, x = 8.00 m

Therefore, the initial velocity in the horizontal, x-direction with which the branch was thrown, 'uₓ', is given as follows;

uₓ = x/t = 8.00 m/((√30)/7 s)

Using a graphing calculator, we get;

uₓ = 8.00 m/((√30)/7 s) = (28/15)·√30 m/s ≈ 10.224 m/s

The initial velocity in the horizontal, x-direction with which the branch was thrown, uₓ ≈ 10.224 m/s.

3 0

3 years ago

Which is an example of potential en

SIZIF [17.4K]

a yoyo in someones hand is an example of potential energy

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3 years ago

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