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3 years ago

I’m a wave , the medium moves parallel to the direction that the wave travels

Physics

2 answers:

Furkat [3]3 years ago

5 0

8. a) Four different-coloured pennants are

going to be hung in a row to decorate a

gymnasium wall. In how many different

orders can the pennants be hung?

b) Repeat part (a) for five differentcoloured pennants.

c) Repeat part (a) for 10

IRINA_888 [86]3 years ago

5 0

Answer:

I agree up there

Explanation:

I take physics on odyssey ware too

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A state patrol officer saw a car start from rest at a highway on-ramp. She radioed ahead to another officer 20 mi along the hig

Vikentia [17]

Answer:

We know from the basic speed distance relation that

$Speed=\frac{Distance}{Time}$

Since the car started from rest and it covered the distance between the 2 officer's in 19 minutes we have speed of the car

$Speed=\frac{Distance}{Time}\\\\Speed=\frac{20}{\frac{19}{60}}=63.16mph$

Which clearly exceeds the limit of $60\frac{mi}{hr}$

5 0

3 years ago

Two bikers are riding a circular

OverLord2011 [107]

ANSWER.no cause they have to be going a the same speed and I doubt that are gonna go at the same speed.

8 0

3 years ago

the total positive charge is QQQ = 1.62×10−6 CC , what is the magnitude of the electric field caused by this charge at point P,

balu736 [363]

Answer:

6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

E= Kq/d^2

Where;

K= Coulombs constant = 9.0 × 10^9 C

q = magnitude of charge = 1.62×10−6 C

d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2

E= 14.58 × 10^3/2.4 × 10^-6

E= 6.1 × 10^9 Nm-1

8 0

3 years ago

1- A train travels 92 kilometers in 3 hours, and then 55 kilometers in 3 hours. What is its average speed?

Hunter-Best [27]

<h3>Answer:</h3>

24.5 km/h
4 17/27 m/s
11/3 m/s²

<h3>Explanation:</h3>

1. The average speed is the ratio of total distance to total time:

... speed = distance/time = (92 km +55 km)/(3 h +3h) = (147 km)/(6 h)

... = 24.5 km/h

2. speed = distance/time = (125 m)/(27 s) = 4 17/27 m/s

3. a = ∆v/∆t = (15 m/s -4 m/s)/(3 s) = 11/3 m/s²

8 0

3 years ago

A 7.8 µF capacitor is charged by a 9.00 V battery through a resistance R. The capacitor reaches a potential difference of 4.20 V

Vaselesa [24]

Answer:

655128 ohm

Explanation:

C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F

V₀ = Voltage of the battery = 9 Volts

V = Potential difference across the battery after time "t" = 4.20 Volts

t = time interval = 3.21 sec

T = Time constant

R = resistance

Potential difference across the battery after time "t" is given as

$V = V_{o} (1-e^{\frac{-t}{T}})$

$4.20 = 9 (1-e^{\frac{-3.21}{T}})$

T = 5.11 sec

Time constant is given as

T = RC

5.11 = (7.8 x 10⁻⁶) R

R = 655128 ohm

3 0

3 years ago