The relationship between gravity and pressure in a nebula is that pressure balances gravity. <span>The </span>pressure<span> exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of </span><span>gravity. The answer is B. </span>
Answer:
Explanation:
Given
Original volume V1=30cm^3 converting to L
=30/1000=0.03L
Constant pressure P= 648 tors
Converting to atm; 648 tors*1atm/760 torr=0.853 atm
Work=984J= 984**1L/101.33=9.7L.atm
Note before
W= -P(Vfinal-Vinitial)
-9.7/0.853+0.03L=11.68L
Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736
Explanation:
According to the Arrhenius equation,
or,
where,
= rate constant at 525K
= rate constant at 545K
= activation energy for the reaction = 185kJ/mol= 185000J/mol (1kJ=1000J)
R = gas constant = 8.314 J/mole.K
= initial temperature = 525 K
= final temperature = 545 K
Now put all the given values in this formula, we get
Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736
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Answer:
A
The upthrust on a floating body is in upwards direction and is equal to the weight of the liquid displaced
B
The upthrust is directly proportional to the density of the liquid in which the solid is immersed
C
The upthrust is directly proportional to the volume of the fluid displaced by a solid
The upthrust acts on the body in upward direction at the center of buoyancy.
Upthrust is equal to the weight of liquid displaced by object and weight of liquid will depend on its density.
Upthrust is F=Vρg ,where V is the volume of liquid displaced and ρ is the density of fluid.
The total lateral pressure acting on an immersed object on one side is equal and in opposite direction to the total lateral pressure acting on the other side.