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Sergeeva-Olga [200]
3 years ago
11

6+5w-9f-3 use w=3 and f=4

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
<span>6+5w-9f-3
Substitute the variables for numbers
6+5(3)-9(4)-3
Multiply 5 by 3 and -9 by 4
6+15-36-3
Combine like terms
Final Answer: -18
</span>
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Evaluate the expression for n =8 <br> 3+7 x n
bonufazy [111]

Answer:n=-83/60 or -1.383

Step-by-step explanation:

4 0
3 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
3 years ago
Sam can rent a canoe for $3 an hour. If he rents the canoe, he would also have to pay $15 for a non-refundable deposit. He has $
Nikitich [7]
So, We Need To Write An Equation. Lets Make Some Variables.
Max Amount He Can Spend: X
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So, Lets Start.
We Can Write:
H = (X - D) / P
Now, Just Plug In The Known Values.
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That Is Our Equation.

Now, Just For Fun, I Will Solve It.
So, We Need To Simplify.
30 - 15 = 15.
So, We Have:
H = 15/3
So, We Know:
15/3 = 5.
So, We Can Substitute 5 for 15/3.
We Get:
H = 5
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Step-by-step explanation:

Remember this from last year Lol

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Need help what the answer
stealth61 [152]
I think that it might be 62,100 because the 6 is in the ten thousands place, and if you divide it by 10, 60,000/10, then it would be 6000. 60,000 is 10 times more than 6,000. Correct me if I'm wrong.
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3 years ago
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