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inysia [295]
4 years ago
10

According to Newton’s second law of motion, an object accelerates in the same direction as the force applied to it.

Physics
1 answer:
Brilliant_brown [7]4 years ago
7 0

Explaination: equal in force, opposite in direction

the statement is false

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A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2m/s to 4 m/s?
Vitek1552 [10]
Here, Initial momentum = mu = 6*2 = 12 Kg m/s
Final momentum = mv = 6*4 = 24 Kg m/s

In short, Your Answer would be Option C

Hope this helps!
6 0
4 years ago
Read 2 more answers
Correlation is:
xz_007 [3.2K]

Answer: The answer is B

Explanation: A correlation generally is a mutual relationship/connection or the process of establishing the relationship/connection between 2+ things

6 0
2 years ago
Ask Your Teacher In the air over a particular region at an altitude of 500 m above the ground, the electric field is 120 N/C dir
strojnjashka [21]

Answer:

1.475\times 10^{-13}\ C/m^3

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

A = Area

h = Altitude = 600 m

Electric flux through the top would be

-110A (negative as the electric field is going into the volume)

At the bottom

120A

Total flux through the volume

\phi=120-110\\\Rightarrow \phi=10A

Electric flux is given by

\phi=\dfrac{q}{\epsilon_0}\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=10A\epsilon_0

Charge per volume is given by

\rho=\dfrac{q}{v}\\\Rightarrow \rho=\dfrac{10A\epsilon_0}{Ah}\\\Rightarrow \rho=dfrac{10\epsilon_0}{h}\\\Rightarrow \rho=\dfrac{10\times 8.85\times 10^{-12}}{600}\\\Rightarrow \rho=1.475\times 10^{-13}\ C/m^3

The volume charge density is 1.475\times 10^{-13}\ C/m^3

7 0
3 years ago
How much current does a 10.0 Ω resistor draw from a 12 V battery?
Amiraneli [1.4K]
The answer would be B.
(V=IR, 12-10i, 12/10=1.2)
7 0
3 years ago
A sprinter starts from rest and runs with constant acceleration to a top speed of 12m/s in 4.0 seconds.
bagirrra123 [75]

Answer:

  a =  3,0 m/s²

Explanation:

En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.

          v= v₀ + a t

como el corredor parte del reposo si velocidad inicial es cero

           v =  at

           a = v/t

calculemos

          a = 12 /4,0

          a =  3,0 m/s²

4 0
3 years ago
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