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Morgarella [4.7K]
3 years ago
11

What is the acceleration of a cabinet of mass 45 kilograms if Jake and Ted push it by applying horizontal force of 25 newtons an

d 18 newtons respectively in the same direction
Physics
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

a=0.96\ m/s^2

Explanation:

Given that,

Mass of cabinet, m = 45 kg

Two horizontal force of 25 newtons and 18 newtons respectively in the same direction.

When the forces are acting in same direction, the net force is equal to the sum of forces i.e.

F = 25 N + 18 N = 43 N

Let a is the aceleration of the cabinet

So,

F = ma

a=\dfrac{F}{m}\\\\a=\dfrac{43}{45}\\\\a=0.96\ m/s^2

So, the acceleration of the cabinet is 0.96\ m/s^2.

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Answer:

The thrown rock will strike the ground 2.42s earlier than the dropped rock.

Explanation:

<u>Known Data</u>

  • y_{i}=300m
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We can use y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find the total time of fall, so 0=300m-\frac{(9.8m/s^{2})t_{D}^{2}}{2}, then clearing for t_{D}.

t_{D}=\sqrt[2]{\frac{300m}{4.9m/s^{2}}} =\sqrt[2]{61.22s^{2}} =7.82s

<u>Time of the Thrown Rock</u>

We can use y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find the total time of fall, so 0=300-29t_{T}-\frac{(9.8)t_{T}^{2}}{2}, then, 0=-4.9t_{T}^{2}-29t_{T}+300, as it is a second-grade polynomial, we find that its positive root is t_{T}=5.4s

Finally, we can find how much earlier does the thrown rock strike the ground, so t_{E}=t_{D}-t_{T}=7.82s-5.4s=2.42s

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