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SashulF [63]
1 year ago
11

Does the refraction of light make a swimming pool seem deeper or shallower? explain your answer.

Physics
1 answer:
larisa [96]1 year ago
6 0

The refraction of light makes a swimming pool seem <u>shallower</u>.

The swimming pool seems shallower because the rays of light coming from the bottom of the pool do not come with a straight path. The path of light is straight as long as it is in the water.

When lights come out of the water into the air it bents downwards. This bending is called refraction.

Refraction forms a virtual image of the pool and it seems shallower than it actually is to the observer. This only happens when light travels from one transparent medium into another having lower density.

If you need to learn more about why a swimming pool appears <u>shallower</u>, click here

https://brainly.in/question/7136803?referrer=searchResults

#SPJ4

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Oduvanchick [21]

Yes, they both cast shadows. A  eclipse occurs when one enters the shadow of the other.

Solar eclipse: Earth in shadow of Moon.

Lunar eclipse: Moon in shadow of Earth.

A solar eclipse is the result of one celestial body being completely or partially obscured by another celestial body along the line of sight of an observer. A solar eclipse occurs when the moon passes between the earth and the sun, obscuring all or part of the sun's disk. A lunar eclipse occurs when the Moon passes through the Earth's shadow, making the Moon's surface completely or partially obscured.

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8 0
2 years ago
A cricket ball is hit by a person what are the action taken in this movement
SSSSS [86.1K]
Hit is the action for the movement
7 0
3 years ago
Read 2 more answers
A car starts from rest with an acceleration of 6
mrs_skeptik [129]

Answer:

t=16.67s

Explanation:

From the question, acceleration from 6m/s^2  \ to \ 0m/s^2 in 10 seconds.

Acceleration function can be written as:-

a_t=6-0.6t

From the acceleration equation, we can obtain the velocity equation:

v(t)=\int\limits^t_b {0} \, dv=\int\limits^t_0 {a(t)} \, dt\\v(t)=\int\limits^t_0 {(6-06t)} \, dt=6t-0.3t^2\\*dv=a(t)dt

We calculate velocity after 10sec from the above v(t) as 30m/s.

To obtain distance travelled after 10 seconds:-

S=\int\limits^{10}_0 {6t-0.3t^2} \, dt=|3t^2-0.1t^3|   \ *lims(10,0)\\ S=200m

Therefore 200m is for 10seconds, and next 200m at 30m/s

Total time=10+\frac{200}{30}=16.67s

4 0
4 years ago
Two balls move away from each other, both traveling at 7 m/s. One has a mass of 2 kg and the other has a mass of 3 kg
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A 300-kg bear grasping a vertical tree slides down at constant velocity. The friction force between the
tree and the bear is
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4 years ago
The free-body diagram below represents the force of several vehicles driving across a bridge. Assume that the bridge is in stati
krek1111 [17]

In order to calculate the unknown reaction force, we need to know that the sum of forces pointing down is equal the sum of the forces pointing up, so all forces will be in equilibrium.

So we have:

\begin{gathered} 17800+150000+13200=121000+x \\ 181000=121000+x \\ x=181000-121000 \\ x=60000 \end{gathered}

7 0
1 year ago
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