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3 years ago

According to the inverse square law of light, if you double your distance to a source, the brightness will...

Physics

2 answers:

blondinia [14]3 years ago

7 0

Answer:

option (b)

Explanation:

According to the inverse square law,

$Brightness \alpha \frac{1}{distance^{2}}$

As the distance is doubles, the brightness becomes one fourth.

It means the brightness decreases by a factor of 4.

Option (b)

GalinKa [24]3 years ago

6 0

Answer:

a. decrease by a factor of 3.

Explanation:

The intensity of light is inversely proportional to the square of distance.

I ∝1/d^2

I= k/d^2

where k is a constant

so, if d becomes 2d , I will be come I/4

Therefore, intensity will a. decrease by a factor of 3.

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Through what voltage must an αα-particle, with its charge of +2e+2e, be accelerated so that it has just enough energy to reach a

mezya [45]

Answer:5101.35v

Explanation:

Radius of gold nucleus=7.3×10-15m and a charge of +79e

Q= 79e

e=1.6×10^-19

q= +2e

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U = 1/(4×3.142×Eo)×(qQ)/r

Where r is distance between the charges and the nucleus

r=R+d

V=U/q

U= 1/(4×3.142×Eo)×Q/r

V= 1/(4×3.142×Eo)×Q/(r+d)

9.0×10^9 ×(79×10^-19)/(7.3×10^-15)+(1.5×10^-14)

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V= 9×10^9×(5.67×10^-14)= 5101.35v

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3 years ago

HELP NEEDED ASAP I'M GIVING BRAINLIEST

guajiro [1.7K]

Answer:

d . A stream of particles

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3 years ago

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A baseball player friend of yours wants to determine his pitching speed. you have him stand on a ledge and throw the ball horizo

zhenek [66]

Answer:

The pitching speed of your friend is 33.20 m/s

Explanation:

Lets explain how to solve the problem

Your friend throw the ball horizontally that means the vertical initial

component of velocity is zero ( $u_{y}=0$ ).

The ball is thrown from a height 4 meters above the ground.

The height $h=u_{y}t+\frac{1}{2}gt^{2}$

Remember: the height is negative value because its below the point of

thrown (initial position)

h = -4 m , $u_{y}=0$ and g = -9.8 m/s²(downward)

Substitute these values in the rule above

⇒ $4=0-\frac{1}{2}(9.8)t^{2}$

⇒ -4 = -4.9t² (multiply both sides by -1)

⇒ 4 = 4.9t² (divide both sides by 4.9)

⇒ 0.81633 = t² (take √ for both sides)

⇒ t = 0.9035

Then the time of the ball to land on the ground is 0.9035 seconds

The range of the ball on the ground is 30 m

The range $R=u_{x}*t$ , where $u_{x}$ is the horizontal

component of the initial velocity

R = 30 meters and t = 0.9035

⇒ $30=u_{x}(0.9035)$ (divide both sides by 0.9035)

⇒ $u_{x}=33.20$ m/s

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3 years ago

The radius of Earth is . The average Earth-Sun distance is . How many Earths would fit between Earth and the Sun if they are sep

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Answer:

The radius of the earth is 6,371 km.

The average Earth-Sun distance is 152.09 million km

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3 years ago

A track begins at 0 meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing for a rac

rosijanka [135]

55 meters. If she started at 10 meters and ran 45 more, 10+45=55.

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4 years ago

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