Answer:
(a).The wavelength of the waves is 0.624 m.
(b). The speed of the waves is 43.74 m/s.
(c). The fundamental frequency of the string is 14.02 Hz.
Explanation:
Given that,
length = 1.56 m
Frequency = 70.1 Hz
Number of loop = 5
(a). We need to the calculate the wavelength of the waves
Using formula of wave length
![\lambda=\dfrac{2L}{n}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B2L%7D%7Bn%7D)
Put the value into the formula
![\lambda=\dfrac{2\times1.56}{5}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B2%5Ctimes1.56%7D%7B5%7D)
![\lambda=0.624\ m](https://tex.z-dn.net/?f=%5Clambda%3D0.624%5C%20m)
(b). We need to calculate the speed of the waves
Using formula of speed
![v= \lambda\times f](https://tex.z-dn.net/?f=v%3D%20%5Clambda%5Ctimes%20f)
Put the value into the formula
![v=0.624\times70.1](https://tex.z-dn.net/?f=v%3D0.624%5Ctimes70.1)
![v=43.74\ m/s](https://tex.z-dn.net/?f=v%3D43.74%5C%20m%2Fs)
(c). We need to calculate the fundamental frequency of the string
Using formula of fundamental frequency
![f'=\dfrac{f}{n}](https://tex.z-dn.net/?f=f%27%3D%5Cdfrac%7Bf%7D%7Bn%7D)
Put the value into the formula
![f'=\dfrac{70.1}{5}](https://tex.z-dn.net/?f=f%27%3D%5Cdfrac%7B70.1%7D%7B5%7D)
![f'=14.02\ Hz](https://tex.z-dn.net/?f=f%27%3D14.02%5C%20Hz)
Hence, (a).The wavelength of the waves is 0.624 m.
(b). The speed of the waves is 43.74 m/s.
(c). The fundamental frequency of the string is 14.02 Hz.