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irga5000 [103]
3 years ago
11

Which is heavier, the earth or the moon

Physics
1 answer:
Aloiza [94]3 years ago
5 0

When you say "heavy", you're talking about the gravitational force
between that object and another object, so it depends on what the
"other object" is.

If the "other object" is, let's say, the sun, then the gravitational attraction
between the Earth and sun is about 80 times as much as the gravitational
attraction between the Moon and sun, because the Earth has about 80 times
the mass of the Moon.

But if, somehow, the weight you have in mind is the gravitational attraction
between the Earth and the Moon, then those forces are equal.  The force
of gravity between two objects depends on the product of both masses,
and it's equal in both directions.

If that isn't clear to you, let me give you this additional fact that's guaranteed
to knock you even further off-balance:

Your weight on the Earth is determined by the product of

                           (your mass) times (the Earth's mass).

The Earth's weight on you is determined by the product of

                           (your mass) times (the Earth's mass).

Your weight on Earth is the same as the Earth's weight on you.

Would you like to prove it ?

-- Turn the bathroom scale upside-down, so that the step-pad
    is on the floor.

-- Then step on it, so that you're standing on the bottom, which
    is facing up.

-- If you placed a little mirror on the floor, so that you can read
   the numbers, which are facing down toward the floor, you'll
   read your own weight, even though with the scale upside-down,
   you're weighing the Earth on you.

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Which of the following waves are mechanical?
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"Ocean waves" is the only example of mechanical waves on that list. 
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3 years ago
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Calculate the minimum average power output necessary for a person to run up a 12.0 m long hillside, which is inclined at 25.0° a
Viktor [21]

Answer:

Power, P = 924.15 watts

Explanation:

Given that,

Length of the ramp, l = 12 m

Mass of the person, m = 55.8 kg

Angle between the inclined plane and the horizontal, \theta=25^{\circ}

Time, t = 3 s

Let h is the height of the hill from the horizontal,

h=l\ sin\theta

h=12\times \ sin(25)

h = 5.07 m

Let P is the power output necessary for a person to run up long hill side as :

P=\dfrac{E}{t}

P=\dfrac{mgh}{t}

P=\dfrac{55.8\times 9.8\times 5.07}{3}

P = 924.15 watts

So, the minimum average power output necessary for a person to run up is 924.15 watts. Hence, this is the required solution.

3 0
3 years ago
There are several forms of energy. Which of the following is not a form of energy?
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A. Is the right answer.
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The height of a typical playground slide is about 1.8 m and it rises at an angle of 30 ∘ above the horizontal.
Salsk061 [2.6K]

Answer:

5.94\ \text{m/s}

1.7

0.577

Explanation:

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

\theta = Angle of slope = 30^{\circ}

v = Velocity of child at the bottom of the slide

\mu_k = Coefficient of kinetic friction

\mu_s = Coefficient of static friction

h = Height of slope = 1.8 m

The energy balance of the system is given by

mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.8}\\\Rightarrow v=5.94\ \text{m/s}

The speed of the child at the bottom of the slide is 5.94\ \text{m/s}

Length of the slide is given by

l=h\sin\theta\\\Rightarrow l=1.8\sin30^{\circ}\\\Rightarrow l=0.9\ \text{m}

v=\dfrac{1}{2}\times5.94\\\Rightarrow v=2.97\ \text{m/s}

The force energy balance of the system is given by

mgh=\dfrac{1}{2}mv^2+\mu_kmg\cos\theta l\\\Rightarrow \mu_k=\dfrac{gh-\dfrac{1}{2}v^2}{gl\cos\theta}\\\Rightarrow \mu_k=\dfrac{9.81\times 1.8-\dfrac{1}{2}\times 2.97^2}{9.81\times 0.9\cos30^{\circ}}\\\Rightarrow \mu_k=1.73

The coefficient of kinetic friction is 1.7.

For static friction

\mu_s\geq\tan30^{\circ}\\\Rightarrow \mu_s\geq0.577

So, the minimum possible value for the coefficient of static friction is 0.577.

8 0
3 years ago
A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is oriented
oee [108]

Answer:

Magnetic flux, \phi=2.22\times 10^{-3}\ Wb

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

\phi=BA\ cos\theta

\phi=0.078\times \pi \times (0.1)^2\ cos(25)

\phi=0.00222\ Wb

or

\phi=2.22\times 10^{-3}\ Wb

So, the magnitude of magnetic flux through the surface is 2.22\times 10^{-3}\ Wb. Hence, this is the required solution.

4 0
4 years ago
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