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Damm [24]
3 years ago
13

The following list contains some common radicals. Using the charges on these ions and the idea of valence, predict the formulas

for the following:_________.
1. nitrate NO3-1 phosphate PO4-3
2. sulfate SO4-2 acetate C2H3O2-1
3. ammonium NH4+ chromate CrO4-2
4. carbonate CO3-2 dichromate Cr2O7-2
5. permanganate MnO4-1 sulfide S-2
6. sodium carbonate
7. potassium permanganate

Chemistry
1 answer:
lesantik [10]3 years ago
3 0

Answer : The formula for the compound sodium carbonate is Na_2CO_3

The formula for the compound potassium permanganate is KMnO_4

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

(a) Sodium carbonate

In the compound, the sodium metal forms an ionic compound with polyatomic anion (carbonate) CO_3^{2-}.

Here, sodium is having an oxidation state of +1 called as Na^{1+} cation and carbonate CO_3^{2-} is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, Na_2CO_3

Hence, the formula for the compound sodium carbonate is Na_2CO_3

(b) Potassium permanganate

In the compound, the potassium metal forms an ionic compound with polyatomic anion (permanganate) MnO_4^{1-}.

Here, potassium is having an oxidation state of +1 called as K^{1+} cation and permanganate MnO_4^{1-} is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, KMnO_4

Hence, the formula for the compound potassium permanganate is KMnO_4

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Answer:

y1 = 0.3162

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Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

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Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
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