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Damm [24]
3 years ago
13

The following list contains some common radicals. Using the charges on these ions and the idea of valence, predict the formulas

for the following:_________.
1. nitrate NO3-1 phosphate PO4-3
2. sulfate SO4-2 acetate C2H3O2-1
3. ammonium NH4+ chromate CrO4-2
4. carbonate CO3-2 dichromate Cr2O7-2
5. permanganate MnO4-1 sulfide S-2
6. sodium carbonate
7. potassium permanganate

Chemistry
1 answer:
lesantik [10]3 years ago
3 0

Answer : The formula for the compound sodium carbonate is Na_2CO_3

The formula for the compound potassium permanganate is KMnO_4

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

(a) Sodium carbonate

In the compound, the sodium metal forms an ionic compound with polyatomic anion (carbonate) CO_3^{2-}.

Here, sodium is having an oxidation state of +1 called as Na^{1+} cation and carbonate CO_3^{2-} is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, Na_2CO_3

Hence, the formula for the compound sodium carbonate is Na_2CO_3

(b) Potassium permanganate

In the compound, the potassium metal forms an ionic compound with polyatomic anion (permanganate) MnO_4^{1-}.

Here, potassium is having an oxidation state of +1 called as K^{1+} cation and permanganate MnO_4^{1-} is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, KMnO_4

Hence, the formula for the compound potassium permanganate is KMnO_4

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The molarity of a solution in which 55. 49 g of calcium chloride is dissolved in enough water to make 500. ml of solution is 1M.

<h3>What is molarity? </h3>

It is defined as number of moles of solute divided by volume of solution.

Given,

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Molarity =0.5×1000/500=1M

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4 0
1 year ago
How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
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The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


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Explanation:

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6 0
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3.
belka [17]

Answer:

3. Inverse 1. Direct

Explanation:

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Whenever you are restricted as "constant" temperature, volume, or pressure...cancel them off of your equation.

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