n = number of moles of sample of octane = 0.07 mol
Q = energy absorbed by a sample of octane = 3.5 x 10³ J
c = molar heat capacity of octane = 254.0 J/K* mol
ΔT = increase in temperature of octane = ?
Heat absorbed is given as
Q = n c ΔT
inserting the values
3.5 x 10³ J = (0.07 mol) (254.0 J/K* mol) ΔT
ΔT = (3.5 x 10³ )/((0.07) (254.0))
ΔT = 196.85 K
hence increase in temperature comes out to be 196.85 K
The answer would be Sperm.
Answer:
Length (nm) Pressure (atm)
5.0 11.7
6.0 9.8
7.0 8.4
8.0 7.2
9.0 6.6
10.0 5.8
Explanation:
This is also PLATOS answer!!
Your answer would be "Chemical Change"
Condensation goes with A.
Evaporation goes with C.
Sublimation goes with B.
Freezing goes with D.
