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3 years ago

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CHEM 100Worksheet 6Summer2021Name:____________________(5pts each, 10 pts total) Complete the following multistep synthesis probl

ems. Show all reagents and intermediates for full credit. You do not need to show the mechanisms.

1 answer:

Whitepunk [10]3 years ago

5 0

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When small pieces of manganese oxide were added to a solution of hydrogen peroxide, water and oxygen were produced. Manganese ox

Evgesh-ka [11]

The change which increase the rate of the reaction is by increasing the amount of solution.

<h3>What is the rate of the reaction?</h3>

Rate of the reaction gives idea about the speed of the completion of the reaction or the formation of the products.

Given chemical reaction is:
2H₂O₂ $\overset{MnO_{2}}{\rightarrow}$ 2H₂O + O₂

In the above chemical reaction MnO₂ acts as a catalyst which helps in increasing the rate of the reaction without being involved in the reaction. So the formation of the product depends only on the concentration of the solution. So, by increasing the solution amount will increase in the rate.

Hence, increasing the amount of solution will increase the rate.

To know more about rate of reaction, visit the below link:
brainly.com/question/7578129

#SPJ1

6 0

1 year ago

The melting points for the compounds li2s, rb2s, and k2s are 900°c, 530°c, and 840°c, respectively. list these three compounds i

Mila [183]

Answer: The order of increasing lattice energy is $Li_2S>K_2S>Rb_2S$

Explanation: Lattice energy is defined as the energy required to break the intermolecular force that is responsible for the formation of a lattice.

Melting point is defined as the temperature at which solid gets converted into liquid due to the weakening of the bonds in the solid form.

Relation between lattice energy and Melting point:

The relationship between these two is direct.

$\text{Lattice energy}\propto \text{Melting point}$

More the melting point of a compound, more will be its lattice energy.

Order of increasing Lattice energy will be:

$Li_2S>K_2S>Rb_2S$

7 0

3 years ago

What is the molecular shape of N2O2?

Anettt [7]

Answer:

If you're just looking at the Lewis Structure from the perspective of the octet rule, it does appear that the structure is correct. Dinitrogen always has a lone pair of electrons which could conceivably be used for dative bonding as you suggest. So from that perspective there appears to be nothing wrong at all - other than that it doesn't exist in nature in this way.

Explanation:

3 0

2 years ago

Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu

Gre4nikov [31]

Answer:

$c=2.0769\ \frac{J}{g\ \textdegree C}$

Explanation:

-Specific heat capacity is given by the formula:

$q=mc\bigtriangleup T$

Where:

$q$ is the heat gained or loosed by the substance

$m$ is the mass of the substance

$c$ is the specific heat of the substance

$\bigtriangleup T$ is the change in temperature

#We make c the subject of the formula and substitute to solve for it:

$q=mc\bigtriangleup T\\\\c=\frac{q}{m\bigtriangleup T}\\\\\bigtriangleup T=(57-32)\textdegree C=25\textdegree C\\\\\therefore c=\frac{6.75\times 10^4J}{1.3\times 1000\ g\times 25\textdegree C}\\\\=2.0769 \ \frac{J}{g\ \textdegree C}$

Hence, the specific heat capacity of the ice is $2.0769 \frac{J}{g\ \textdegree C}$

8 0

3 years ago

Determine the equilibrium constant, Keq, at 25°C for the reaction

adelina 88 [10]

Explanation:

The given chemical reaction is:

$2Br^- (aq) + I_2(s) Br_2(l) + 2I^- (aq)$

$E^ocell=oxidation potential of anode + reduction potential of cathode\\$

The relation between Eo cell and Keq is shown below:

$deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell$

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

$E^ocell= (-1.07+0.53)V\\=-0.54V$

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

$ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3$

Answer:

Keq=6.13x10^33

3 0

2 years ago