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Over [174]
4 years ago
13

At what distance will a 45 W lightbulb have the same apparent brightness as a 130 W bulb viewed from a distance of 35 m ? (Assum

e that both bulbs convert electrical power to light with the same efficiency, and radiate light uniformly in all directions.)
Physics
1 answer:
Sloan [31]4 years ago
5 0

Answer:

20.6 m

Explanation:

P₁ = Power of first bulb = 45 W

P₂ = Power of second bulb = 130 W

r₁ = distance from the first bulb

r₂ = distance from the second bulb = 35 m

Using the equation

\frac{P_{1}}{r_{1}^{2}} = \frac{P_{2}}{r_{2}^{2}}

Inserting the values

\frac{45}{r_{1}^{2}} = \frac{130}{35^{2}}

r₁ = 20.6 m

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A space rover weighs less on Mars than it does on Earth. Which statement explains this difference? A. The gravitational constant
Maksim231197 [3]

Answer:

B. The mass of Mars is less than the mass of Earth.

Explanation:

Mass of an object is the constant anywhere in the universe.

The weight of an object is equal to the gravitational force acting on it.

Weight is given by

W=\dfrac{GMm}{R^2}\\\Rightarrow W=\dfrac{GM}{R^2}m\\\Rightarrow W=mg

where

G = Gravitational constant

M = Mass of Planet

R = Radius of planet

m = Mass of object

g = Acceleration due to gravity

So weight of an object depends on the acceleration due to gravity on that planet. The acceleration due to gravity depends on the mass and radius of the planet.

The weight of the object is less on Mars because mars has less mass compared to Earth.

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3 years ago
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Answer:20,30

50,100

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4 years ago
If an object aquires additional energy, it is also aquiring additional: a) taxes b) vitamins c) mass d) pressure e) buoyancy
ludmilkaskok [199]

Answer:

Option c) mass

Explanation:

With the increase in energy in energy of an object there will be an increase in its mass.

Also from Einstein's mass-energy equivalence,

E = mc^{2}

where

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c = speed of the object (usually speed of light or close to it)

which states that energy and mass are inter convertible.

From which it can be concluded that if an object acquires additional energy, it also acquires additional mass.

3 0
4 years ago
If the activity of a radionuclide decreases from 5,000 disintegrations per minute to 625 disintegrations per minute
lys-0071 [83]

Answer:

4 hrs

Explanation:

625 = 5000 (1/2)^n

625/5000 = 1/2^n

n = 3 half lives

3 half lives = 12 hours       1 half life = 4 hrs

7 0
3 years ago
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