Mass of the car = 1200 kg
Mass of the truck = 2100 kg
Total mass of car and truck = 2100 + 1200 = 3300 kg
Since, the car pushes the truck. Hence, they will move together and will have same acceleration.
Let the acceleration be a.
According to Newton's second law:
F(net) = ma
F = 4500 N
4500 = 3300 × a

a = 1.36 m/s^2
Let the force applied by the car on truck be F.
F = F(net) on the truck
F = ma
F = 2100 × 1.36
F = 2856 N
Hence, the force applied by the car on the truck is 2856 N
If the force is removed, then there are no other forces acting on the object, the object will continue to move at constant velocity, meaning that it would move in a line tangent to the circular path.
winter temperature is lower so air molecules move slower n the pressure is lower. ans is A) slower, low
D) Yes. Even though the initial and final velocities are the same, there is a change in direction for the ball.
Acceleration (a) = change in velocity (v) over time (t), let's consider moving right is (+) and moving left is (-)
a = (vf - vi)/t = (-5 - +5)/t
a = (-10)/t
So even though the number looks the same from vi to vf, there actually is a negative acceleration of 10m/s/s.