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3 years ago

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A jet airplane is in level flight. The mass of the airplane is m=9010kg. The airplane travels at a constant speed around a circu

lar path of radius R=9.77mi and makes one revolution every T=0.129h. Given that the lift force acts perpendicular upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane? At what angle is the airplane banked?

1 answer:

Lyrx [107]3 years ago

3 0

Answer:

The magnitude of the lift force L = 92.12 kN

The required angle is ≅ 16.35°

Explanation:

From the given information:

mass of the airplane = 9010 kg

radius of the airplane R = 9.77 mi

period T = 0.129 hours = (0.129 × 3600) secs

= 464.4 secs

The angular speed can be determined by using the expression:

ω = 2π / T

ω = 2 π/ 464.4

ω = 0.01353 rad/sec

The direction $\theta = tan^{-1} ( \dfrac{\omega ^2 R}{g})$

$\theta = tan^{-1} ( \dfrac{0.01353 ^2 \times (9.77\times 1609)}{9.81})$

θ = 16.35°

The magnitude of the lift force L = mg ÷ Cos(θ)

L = (9010 × 9.81) ÷ Cos(16.35)

L = 88388.1 ÷ 0.9596

L = 92109.32 N

L = 92.12 kN

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A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the

Digiron [165]

Answer:

A. W = 6875.0 J.

B. W = -14264.6 J.

Explanation:

A. The work done by the rider can be calculated by using the following equation:

$W_{r} = |F_{r}|*|d|*cos(\theta_{1})$

Where:

$F_{r}$ : is the force done by the rider = 25 N

d: is the distance = 275 m

θ: is the angle between the applied force and the distance

Since the applied force is in the same direction of the motion, the angle is zero.

$W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J$

Hence, the rider does a work of 6875.0 J on the bike.

B. The work done by the force of gravity on the bike is the following:

$W_{g} = |F_{g}|*|d|*cos(\theta_{2})$

The force of gravity is given by the weight of the bike.

$F_{g} = -mgsin(24)$

And the angle between the force of gravity and the direction of motion is 180°.

$W_{g} = |mgsin(24)|*|d|*cos(\theta_{2})$

$W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J$

The minus sign is because the force of gravity is in the opposite direction to the motion direction.

Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.

I hope it helps you!

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3 years ago

A car travels in a straight line covering a total distance of 90.0 miles in 60.0 minutes. Which one of the following statements

andrezito [222]

Answer:

E) The average velocity of the car is 90.0 miles per hour in the direction of motion.

Explanation:

Given;

distance covered by the car, d = 90 miles

time taken, t = 60 minutes = 1 hour

The average velocity of the car is given by change in displacement per change in time;

V = Δd / Δt

$V = \frac{x_f - x_o}{t_f -t_o} = \frac{90-0}{1-0} \\\\V = 90 \ miles/hour$

Therefore, the average velocity of the car is 90.0 miles per hour in the direction of motion.

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3 years ago

1. A buoyant force of 790 N lifts a 214 kg sinking boat.What is the boat's<br> net acceleration?

enot [183]

Answer:

The net acceleration of the boat is approximately 6.12 m/s² downwards

Explanation:

The buoyant or lifting force applied to the boat = 790 N

The mass of the boat lifted by the buoyant force = 214 kg

The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;

Fₐ = F - W

The weight of the boat = 214 × 9.81 = 2099.34 N

Therefore;

Fₐ = 790 - 2099.34 = -1309.34 N

Fₐ = Mass of the boat × The acceleration of the boat

Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;

F = Mass of the boat × The net acceleration of the boat

F = -1309.34 N = 214 kg × The net acceleration of the boat

∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²

The net acceleration of the boat ≈ 6.12 m/s² downwards

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You have given a power supply, copper wire, and an iron nail. What should you do to decrease the strength of the electro magnet?

Viefleur [7K]

Explanation:

If you wrap some of the wire around the nail in one direction and some of the wire in the other direction, the magnetic fields from the different sections fight each other and cancel out, reducing the strength of your magnet

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3 years ago

If your weight is 588N on the earth, how far should you go from the centre of the earth so that your weight will be 300N? The ra

Rom4ik [11]

Answer:

Hmm, Well I am pretty sure the answer is 288N

Explanation:

I got the answer 288N but I am not sure if that is correct. Hope it helps! :D

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3 years ago