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jekas [21]
3 years ago
10

A machine produces a larger force than you exert to operate the machine. How does this input distance of the machine compare to

its output distance?
Physics
1 answer:
arlik [135]3 years ago
7 0

Answer:

Because the output force is greater than the input force, the input distance must be greater than the output distance.

Explanation:

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How long does it take to drive from one end of california to the other?
evablogger [386]

California is the third largest state and the only two bigger states than California are Alaska and Texas so it really depends on how you want to cross it. There are two routes to cross California depending on how you plan your visit and places you need to see. Depending on the route you take crossing California can take from twelve to almost sixteen hours of drive. 

8 0
3 years ago
Which wave has a longer period and how many times, the wave with a frequency of 7000Hz or the wave with a frequency of 21.000Hz?
Nuetrik [128]

Answer:

I would say the answer is the wave of 21.000Hz

Explanation:

Because it has more frequency, and as more frequency you add, the time or longer period also increases.

3 0
3 years ago
What type of weather would be in the middle of the picture, where the barometric pressure is 1000 millibars?
UkoKoshka [18]
It would be D. Hope that helped :)
4 0
3 years ago
What is kinematics..???​
swat32

Answer:

Kinematics is the study of motion, without any reference to the forces that cause the motion. It basically means studying how things are moving, not why they're moving. It includes concepts such as distance or displacement, speed or velocity, and acceleration, and it looks at how those values vary over time.

7 0
3 years ago
A 15.0-μF capacitor is charged by a 130.0-V power supply, then disconnected from the power and connected in series with a 0.280-
SVETLANKA909090 [29]

The resonant frequency of a circuit is the frequency \omega_0 at which the equivalent impedance of a circuit is purely real (the imaginary part is null).

Mathematically this frequency is described as

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

Where

L = Inductance

C = Capacitance

Our values are given as

C = 15*10^{-6}\mu F

L = 0.280*10^{-3}mH

Replacing we have,

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

f = \frac{1}{2\pi}(\sqrt{\frac{1}{(15*10^{-6})(0.280*10^{-3})}})

f= 2455.81Hz

From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.

For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.

7 0
3 years ago
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