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zalisa [80]
3 years ago
12

A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second 2. What is the net force on the car?

Physics
1 answer:
Elodia [21]3 years ago
3 0

Newton #2:     F = M a

               (1 x 10³ kg) (4.5 m/s²)  =  4,500 newtons  
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A displacement vector is 34.0 m in length and is directed 60.0° east of north. What are the components of this vector? Northward
PolarNik [594]

Answer:

A)  29.4 m 17.0 m; B) 2 m

Explanation:

If a vector is 34.0 m in length and is directed 60.0° east of north (which means 30.0° over the horizontal), then its coordinates will be:

Horizontal: (34.0 m)cos(30.0°)=29.4 m

Vertical: (34.0 m)sin(30.0°)=17 m

If one person walks 8.0 meters in a straight line and then walks 5.0 meters in another straight line, then the minimum displacement would be to go back over his tracks, displacing himself 8m-5m=3m, while the maximum displacement would be going straight ahead, displacing himself 8m+5m=13m. Any answer outside this interval is impossible (2m).

8 0
3 years ago
A machine is supplied Energy at a rate of 4000 W and does useful work at a rate of 3760 W. What is the efficiency of the machine
ICE Princess25 [194]
The efficiency of a machine is the ratio between the output power and the power in input:
\epsilon =  \frac{P_{out}}{P_{in}}
in our problem, the output power is 3760 W while the input power is 4000 W, so the efficiency is
\epsilon =  \frac{3760 W}{4000 W} =0.94
So the efficiency of the machine is 94%.
6 0
3 years ago
Read 2 more answers
A pendulum of length L = 1 m is released from an initial angle of 15° . After 1000 s, its amplitude is reduced to 2.5º. What is
jonny [76]

Answer:

The value of the time constant is 558.11 sec.

Explanation:

Given that,

Pendulum length = 1 m

Initial angle = 15°

Time = 1000 s

Reduced amplitude = 2.5°

We need to calculate the value of the time constant

Using formula of damping oscillation

\theta=\theta_{0}e^{\dfrac{t}{\tau}}

Where, \theta =amplitude

\theta_{0} =amplitude at t = 0

Put the value into the formula

2.5=15e^{\dfrac{-1000}{\tau}}

\dfrac{1}{6}=e^{\dfrac{-1000}{\tau}}

ln\dfrac{1}{6}=\dfrac{-1000}{\tau}

\tau=\dfrac{1000}{-ln\dfrac{1}{6}}

\tau=558.11\ sec

Hence, The value of the time constant is 558.11 sec.

6 0
3 years ago
A radioactive isotope of potassium has a half-life of 20 minutes if a 40 g sample of this isotope is allowed to decay for 80 min
FinnZ [79.3K]

There will be 2.5g left.


Explanation:

80/20 = 4 half lives

40/2 = 20

20/2 = 10

10/2=5

5/2 = 2.5


5 0
3 years ago
An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves with
Ipatiy [6.2K]

Answer:

The object´s displacement vector is Δr =  8i - 6 j  

Explanation:

Hi there!

The position vector is given by the following function:

r = t²i - (3t + 3) j

Let´s find the position of the object at time t1 and t2:

At t1 = 1 s:

r1 = (1)² i - (3 · (1) + 3 )j

r1 = 1 i - 6 j

At t2 = 3 s:

r2 = (3)² i - (3 · (3) + 3) j

r2 = 9 i - 12 j

The displacement is calculated as follows:

displacement = Δr = final position - initial position = r2 - r1

r2 - r1 = 9 i - 12 j - (1 i - 6 j)

r2 - r1 = 9 i - 12 j - 1 i + 6 j

r2 - r1 = 8 i - 6 j

The object´s displacement vector is Δr =  8i - 6 j  

8 0
3 years ago
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