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3 years ago

A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second 2. What is the net force on the car?

Physics

1 answer:

Elodia [21]3 years ago

3 0

Newton #2: F = M a

(1 x 10³ kg) (4.5 m/s²) = 4,500 newtons

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Consider two air-filled parallel-plate capacitors with circular plates. Capacitor 1 has a distance between plates d and plate ra

sergey [27]

Answer:

1/8 x C

Explanation:

The capacitance of parallel plate capacitor

= ε₀ A /d where A is area of plate and d is distance between plate.

for capacitor 1

C = ε₀ A /d

For capacitor 2

radius = R/2

Area = A / 4

Capacitance

= ε₀ (A/4) x ( 1 / 2d )

= ( 1 / 8) x (ε₀ A /d)

= 1/8 x C

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3 years ago

Two forces, F1 and F2 (with F1 > F2), act on an object of mass m. The two forces act along the same line but in opposite dire

natali 33 [55]

Here we can use Newton's II law to find the acceleration of the car

$F_{net} = ma$

here we know that

$F_{net} = F_1 - F_2$

as we know that two forces are equal in magnitude but opposite in direction so in order to find net force we need to subtract it

now from above equation

$F_1 - F_2 = ma$

$a = \frac{(F_1 - F_2)}{m}$

so here option A is correct

5 0

3 years ago

A sound with a lot of energy is ____________________ than a sound with less energy.

Zielflug [23.3K]

Louder than a sound with less energy

3 0

1 year ago

A parallel-plate capacitor in air has a plate separation of 1.76 cm and a plate area of

Monica [59]

Answer:

Explanation:

Plate separation, d = 1.76 cm = 0.0176 m

Area of plates, A = 25 cm^2 = 0.0025 m^2

V = 255 V

(a) Capacitance of capacitor

$C = \frac{\epsilon _0A}{d}$

$C = \frac{8.854\times 10^{-12}\times 0.0025}{0.0176}$

C = 1.258 x 10^-12 F

charge is same before and after immersion as the battery is disconnected

q = C V

q = 1.258 x 10^-12 x 255 = 3.2 x 10^-10 C

(b)

Capacitance before, C = 1.258 x 10^-12 C

capacitance after, C' = k x C = 80 x 1.258 x 10^-12 = 100.64 x 10^-12 C

Where, k is the dielectric constant of water = 80

Potential difference after immersion, V' = V / k = 255 / 80 = 3.1875 V

$U = \frac{q^{2}}{2C}$

$U = \frac{(3.2\times 10^{-10})^{2}}{2\times 1.258\times 10^{-12 }}=4.07\times 10^{-8}J$

Final energy

$U' = \frac{q^{2}}{2C'}$

$U' = \frac{(3.2\times 10^{-10})^{2}}{2\times 100.64\times 10^{-12}}=5.08\times 10^{-10}J$

6 0

3 years ago

(4 points) A mother with mass m1 is skating at velocity v1 behind her daughter whose mass is m2, who is skating at v2 . Instead

STatiana [176]

Answer:

B) collision is inelastic because they stick together after collision and share a common final velocity Vf

C) M1V1 + M2V2 = (M1 + M2)Vf

D) Vf = 6.33m/s

E) force = 3040N

Explanation:

Detailed explanation and calculation is shown in the image below

3 0

3 years ago