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Klio2033 [76]
3 years ago
15

A displacement vector is 34.0 m in length and is directed 60.0° east of north. What are the components of this vector? Northward

Eastward choice component component 1 29.4 m 17.0 m 2 18.2 m 28.1 m 3 22.4 m 11.5 m 4 17.0 m 29.4 m 5 25.2 m 18.2 m A) Choice 1 B) Choice 2 C) Choice 3 D) Choice 4 E) Choice 5 79) If I walk 8.0 meters in a straight line and then walk 5.0 meters in another straight line, the total displacement cannot have a magnitude of A) 8 m. B) 2 m. C) 13 m. D) 5 m. E) 3 m.
Physics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

A)  29.4 m 17.0 m; B) 2 m

Explanation:

If a vector is 34.0 m in length and is directed 60.0° east of north (which means 30.0° over the horizontal), then its coordinates will be:

Horizontal: (34.0 m)cos(30.0°)=29.4 m

Vertical: (34.0 m)sin(30.0°)=17 m

If one person walks 8.0 meters in a straight line and then walks 5.0 meters in another straight line, then the minimum displacement would be to go back over his tracks, displacing himself 8m-5m=3m, while the maximum displacement would be going straight ahead, displacing himself 8m+5m=13m. Any answer outside this interval is impossible (2m).

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Calculate the induced electric field (in V/m) in a 40-turn coil with a diameter of 18 cm that is placed in a spatially uniform m
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Answer:

ε = 6.617 V

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Two simple pendulum of slightly different length , are set off oscillating in step is a time of 20s has elasped , during which t
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Answer:

Length of longer pendulum = 99.3 cm

Length of shorter pendulum = 82.2 cm

Explanation:

Since the longer pendulum undergoes 10 oscillations in 20 s, its period T = 20 s/10 = 2 s.

From T = 2π√(l/g), the length of the pendulum. l = T²g/4π²

substituting T = 2s and g = 9.8 m/s² we have

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So, n₂ = n₁ + x. Also n₁ = t/T₁ and n₂ = t/T₂ where T₂ = period of shorter pendulum.

t/T₂ = t/T₁ + x

1/T₂ = 1/T₁ + x  (1)

Also, the T₂ = t/n₂ = t/(n₁ + x)  (2)

From (1) T₂ = T₁/(T₁ + x) (3)

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l = T²g/4π²

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