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asambeis [7]
3 years ago
8

A compound composed of nickel and fluorine contains 9.11 g ni and 5.89 g f. what is the empirical formula of this compound

Chemistry
1 answer:
aalyn [17]3 years ago
6 0
Empirical formula is the simplest formula showing the simplest ratio of atoms in a compound. Calculated as shown;
 we start by calculating the number of moles of each atom;
moles of nickel = 9.11 g ÷ 58.7 g = 0.155 moles 
moles of fluorine = 5.89 g ÷ 19 g = 0.31 moles
Then we get the ratio of the moles of nickel to that of flourine
 That is 0.155 : 0.31  (dividing by the smallest)
            0.155/0.155 : 0.31/0.155
we get 1:2  ( the simplest ratio)
Therefore the empirical formula is nif2 
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Answer:

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Explanation:

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An example of a metal being reduced is;

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3 years ago
The density of mercury is 13.5g/mL. What is the volume of this liquid if the sample weighs 12.5 pounds?
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Answer : The volume of liquid is 420 mL.

Explanation :

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\text{Density}=\frac{\text{Mass}}{\text{Volume}}

As we are given:

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Conversion used:

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Now putting all the given values in this formula, we get:

13.5g/mL=\frac{5670g}{\text{Volume}}

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2 years ago
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