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Black_prince [1.1K]
3 years ago
8

6th grade science i mark as brainliest​

Chemistry
2 answers:
MaRussiya [10]3 years ago
7 0
C is the correct answer
valentinak56 [21]3 years ago
5 0

Answer:

the answer you have marked is correct.

C is correct.

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wolverine [178]
Organisms and burned
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When light bends around an object, the light is
Elan Coil [88]
The answer is REFRACTED
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When aqueous solutions of Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the mass of PbSO4 formed when 1.25 L of 0
neonofarm [45]

Answer:

The mass of PbSO4 formed 15.163 gram

Explanation:

mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625

mole of Na₂SO₄ = 2 x 0.025 = 0.05

                                      Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃

( Mole/Stoichiometry )    \frac{0.0625}{1}           \frac{0.05}{1}

                                     = 0.0625     = 0.05

From  (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.

Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄

                                            = 0.05 x 303.26 g

                                            = 15.163 g

7 0
3 years ago
What could you change or add to your models based on what you have learned about molecules and phases so far?
timurjin [86]

Answer:Phase changes require either the addition of heat energy (melting, evaporation, and sublimation) or subtraction of heat energy (condensation and freezing). ... Changing the amount of heat energy usually causes a temperature change.

Explanation:

5 0
2 years ago
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He wants to increase the energy of emitted electrons . Based on the research of Albert Einstein, what is the best way for him to
pishuonlain [190]

To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

<h3>What is energy of emitted electron?</h3>

The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.

Ee = E - W

<h3>Energy of the emitted electron</h3>

The energy of emitted electrons based on the research of Albert Einstein is given as;

E = hf

where;

  • h is planck's constant
  • f is frequency of incident light on the metal

Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

Learn more about energy of electron here: brainly.com/question/11316046

#SPJ1

8 0
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