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Alexeev081 [22]
3 years ago
12

Which change occurs when an atom in excited state returns to ground state? 1 energy is emitted 2energy is absorbed 3 the number

of electrons decreases 4 the number of electrons increases
Chemistry
2 answers:
kozerog [31]3 years ago
7 0
The answer is number 1 - energy is emitted


Energy is released when an atom in an excited state returns to the ground state.
blondinia [14]3 years ago
4 0

The correct option is this: ENERGY IS EMITTED.

An atom, which is in an excited state is an atom that has moved away from the ground level as a result of gaining energy. This type of atom has more energy compare to those in the ground state and it is also unstable. To return to the ground state, the atom has to emit the energy which it gained in the first instance. Thus, when an excited atom returns to the ground state, energy is always emitted.

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An acid with a H+ molarity of 1x10^-3 M has a PH of?
hichkok12 [17]

Answer:

The answer to your question is pH = 3

Explanation:

Data

[H⁺] = 1 x 10⁻³

pH = ?

pH is a measure of the hydrogen concentration. It measures the acidity or alkalinity. The range of pH goes from 0 to 14. The pH for an acid is from 0 to 6.9, for a neutral solution is 7.0 and for an alkali is from 7.1 to 14.

Formula

             pH = -log [H⁺]

-Substitution

             pH = -log [1 x 10⁻³]

-Simplification

             pH = - (-3)

-Result

             pH = 3

4 0
3 years ago
An element initially weighed 3.555 g. When it was burned in oxygen an oxide compound was produced. The product mass was 4.666 g.
lesya692 [45]
A)
The additional mass is that of Oxygen
4.666 - 3.555
= 1.111 g
B)
The percentage mass of oxygen can be obtained by:
[(mass of Oxygen)/ (Total mass of product)]  * 100
= (1.111 / 4.666) * 100
= 23.81%
5 0
4 years ago
A 2.83 g piece of zinc (density = 7.14 g/ml) is added to a graduated cylinder that contains 12.13 ml H2O. What will be the final
Maslowich

The final volume reading on the graduated cylinder is 12.52ml

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.83/7.14

Volume of zinc = 0.3963

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3963

Total volume = 12.5263 = 12.52 ml

To know more about volume to go the given link :

brainly.com/question/11510153

3 0
2 years ago
128 mL of 1.50 x 10-2 M NaOH is used to titrate 225 mL of a monoprotic acid with unknown concentration to reach the equivalence
mash [69]
M1V1 = M2V2
128(.015) = 225M2
M2 = 8.53x10^-3 or D
4 0
3 years ago
Read 2 more answers
For the reactions below, describe the reactor system and conditions you suggest to maximize the selectivity to make the desired
alexandr1967 [171]

Answer:

hello your question lacks the required reaction pairs below are the missing pairs

Reaction system 1 :

A + B ⇒ D  -r_{1A}  = 10exp[-8000K/T]C_{A}C_{B}

A + B ⇒ U -r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}

Reaction system 2

A + B ⇒ D  -r_{1A} = 10exp( -1000K/T)C_{A}C_{B}

B + D ⇒ U  -r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}

Answer : reaction 1 : description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

reaction 2 :

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

Explanation:

Reaction system 1 :

A + B ⇒ D  -r_{1A}  = 10exp[-8000K/T]C_{A}C_{B}

A + B ⇒ U -r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}

the selectivity of D is represented  using the relationship below

S_{DU} = \frac{-r1A}{-r2A}

hence SDu = 1/10 * \frac{exp(-800K/T)}{exp(-1000K/T)} * C_{A} ^{0.5} C_{B} ^{-0.5}

description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

Reaction system 2

A + B ⇒ D  -r_{1A} = 10exp( -1000K/T)C_{A}C_{B}

B + D ⇒ U  -r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}

selectivity of D

S_{DU} = \frac{-r1A}{-r2A}

hence Sdu = 1/10^7  *  \frac{exp(-1000K/T)}{exp(-10000K/T)} *\frac{C_{A} }{C_{D} }

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

3 0
4 years ago
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