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Olin [163]
3 years ago
7

A resistor R and a capacitor C are connected in series to a battery of terminal voltage V0. Which of the following equations rel

ating the current I in the circuit and the charge Q on the capacitor describes this circuit?
(A) V0 + QC – I2R = 0
(B) V0 – Q/C – IR = 0
(C) V02 – Q2/2C – I2R = 0
(D) V0 – CI – I2R = 0
(E) Q/C – IR = 0
Physics
1 answer:
Lesechka [4]3 years ago
5 0
Answer-C VO2-Q2/2C-I2R=0
Q1/2C currents upon the charge I2R on the capacitor. Voltage V02 goes best
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How many neutrons does element X have if it’s atomic number is 28 and it’s mass number is 81?
Sauron [17]

Answer:

53

Explanation:

M-A=N

Mass-Atomic #= Neutrons

81-28= 53

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3 years ago
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Which configuration would produce an electric current? A) Rotate a coil of copper wire between two magnets. B) Connect a wire be
FrozenT [24]

the answer is (A) the movement of the magnet relative to the coil

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Whose geocentric model of the solar system was accepted for 1400 years
-BARSIC- [3]

Answer:

Plato, Aristotle developed it further and used for 1400 years till Copernicus.

Explanation:

8 0
3 years ago
A space probe is fired as a projectile from the Earth's surface with an initial speed of 2.05 104 m/s. What will its speed be wh
Elanso [62]

Answer:

The value is  v  =  2.3359 *10^{4} \ m/s

Explanation:

From the question we are told that

  The  initial speed is u =  2.05 *10^{4} \  m/s

 Generally the total energy possessed by the space probe when on earth is mathematically represented as

             T__{E}} =  KE__{i}} +  KE__{e}}

Here  KE_i is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

          KE_i =   \frac{1}{2}  *  m  *  u^2

=>       KE_i =   \frac{1}{2}  *  m  *  (2.05 *10^{4})^2

=>       KE_i =  2.101 *10^{8} \ \ m \ \ J

And  KE_e is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

       KE_e =  \frac{1}{2}  *  m *  v_e^2

Here v_e is the escape velocity from earth which has a value v_e =  11.2 *10^{3} \  m/s

=>    KE_e =  \frac{1}{2}  *  m *  (11.3 *10^{3})^2

=>    KE_e =  6.272 *10^{7} \  \  m  \ \   J

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

        KE_p =  \frac{1}{2}  *  m *  v^2

Generally from the law energy conservation we have that

        T__{E}} =  KE_p

So

       2.101 *10^{8}  m  +  6.272 *10^{7}  m  =   \frac{1}{2}  *  m *  v^2

=>     5.4564 *10^{8} =   v^2

=>     v =  \sqrt{5.4564 *10^{8}}

=>     v  =  2.3359 *10^{4} \ m/s

4 0
2 years ago
PLS ANSWER ASAP!!
Molodets [167]

b) between poles M1 and M2

Explanation:

From the expression, we can deduce that r is the distance between two magnetic poles M1 and M2.

The law of attraction between two magnetic poles states that:

<em>  the force of attraction or repulsion between two magnetic poles is a function of the product of the strength of the magnetic poles and the square of the distance between the pole</em>s

 

    Mathematically:

            FM = K \frac{M1 M2}{r^{2} }

 here r is the distance between the poles

  FM is the magnetic force between the poles

   M1 is the strength of the first magnetic pole

   M2 is the strength of the second pole

   K is the magnetic field constant

learn more:

magnetic pole brainly.com/question/2191993

#learnwithBrainly

8 0
3 years ago
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