Refer to the diagram shown below.
u = 0, the initial vertical velocity
Assume g = 9.8 m/s² and ignore air resistance.
At the first stage of landing on the ground, the distance traveled is
h = 3.1 - 0.6 = 2.5 m.
If v = the vertical velocity at this stage, then
v² = u² + 2gh
v² = 2*(9.8 m/s²)*(2.5 m) = 49 (m/s)²
v = 7 m/s
At the second stage of landing on the ground, let a = the acceleration (actually deceleration) that his body provides to come to rest.
The distance traveled is 0.6 m.
Therefore
0 = (7 m/s)² + 2(a m/s²)*(0.6 m)
a = - 49/1.2 = - 40.833 m/s²
Answers:
(a) The velocity when the man first touches the ground is 7.0 m/s.
(b) The acceleration is -40.83 m/s² (deceleration of 40.83 m/s²) to come to rest within 0.6 m.
Answer:
During the fall in September, the Sun passes from northern hemisphere towards equator. ... On this day, Sunlight directly falls on the equator i.e. the sun crosses celestial equator. Day time is equal to night time in the two hemispheres
Explanation:
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Answer:
You are pulled towards that building. At the same time, that building is pulled towards you. Neither object creates enough gravitational force to really do anything. That is why you never notice any affect by either body, (you and a building).
Explanation:
You will surely get attracted towards the building.But it takes a lot of time depending on their masses.
This happens only when you are away from earth with that building.
Both of you will get attracted to it
if a third party with mass more than you or building is with you.
If it is on the earth.. Then the gravity between you and the building is negligible compared to the earth.Hence you will not get attracted towards the building in this case.
Hi, I didn’t understand too well your question, but I hope this helps!
Archimedes principle is based on the weight of the object to push the object upward. Law of floation is the priciple which tells us about the density of the object with the liquid in which it is placed.
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Answer:</h3>
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Explanation:</h3>
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S=3 m²
F=900 N
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p - ?
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p=F/S=900 N / 3 m² = 300 Pa