To cite a source is to ______.

Physics

1 answer:

Aliun [14]3 years ago

3 0

Answer:

Explanation:

Mark as brailiest >_<

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What is the longest wavelength of radiation with enough energy to break carbon-carbon bonds?

iogann1982 [59]

The longest wavelength of radiation used to break carbon-carbon bonds is 344 nm.

Explanation:

The longest wavelength of radiation can also be stated as the minimum radiation frequency required to cut carbon-carbon bond should be equal to the threshold energy of the carbon-carbon bonds.

The threshold energy will be equal to the binding energy of the carbon-carbon bonds. As it is known that carbon-carbon bonds exhibit a binding energy of 348 kJ/mole, the threshold energy to break it, is determined as followed.

First, we have to convert the energy from kJ/mol to J, i.e., energy for the carbon-carbon molecules,

$\text { Energy } = \frac{348 \mathrm{KJ} / \mathrm{mol}}{6.023 \times 10^{23} \text { photons }} \times 1 \text { mole } \times 1000 = 57.77 \times 10^{-20} = 5.78 \times 10^{-19} J$

As,

$E=h v=\frac{h c}{\lambda}$

So,

$\lambda=\frac{h c}{E}=\frac{6.626 \times 10^{-34} \times 3 * 10^{8}}{5.78 \times 10^{-19}}=3.44 \times 10^{-7}$

Thus, $\lambda=344 \mathrm{nm}$ is the longest wavelength of radiation used to break carbon-carbon bonds.

5 0

2 years ago

Heart cells must contract simultaneously to move blood.

krek1111 [17]

Answer:

A

Explanation:

The heart cells must contract simultaneously to move blood.

This means that it needs to act fast and efficiently.

Therefore, the connections among heart cells are characterized by :

having many branches
having many communicating junctions

The correct option should be A

4 0

2 years ago

Read 2 more answers

A 25 kg child runs at a speed of 5.0 m/s and jumps onto a stationary shopping cart and holds on for dear life. The cart has mass

makkiz [27]

Answer:

3.38 m/s

Explanation:

Mass of child = m₁ = 25

Initial speed of child = u₁ = 5 m/s

Initial speed of cart = u₂ = 0 m/s

Mass of cart = m₂ = 12 kg

Velocity of cart with child on top = v

This is a case of perfectly inelastic collision

$m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\frac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\frac{25\times 5+12\times 0}{25+12}\\\Rightarrow v=\frac{125}{37}\\\Rightarrow v=3.38\ m/s$