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dsp73
3 years ago
5

Compute the maximal area obtainable if we assume that the farmer builds a field in the shape of an isosceles triangle, where the

two equal sides are the fenced sides, and the third side is the river.
Mathematics
1 answer:
Tema [17]3 years ago
6 0

The maximal area obtainable if we assume that the farmer builds a field in the shape of an isosceles triangle, where the two equal sides are the fenced sides, and the third side is the river is determined using the same formula used in getting the area of an isosceles triangle.

 

THE FORMULA

Multiply the base (length of the side of the river) and the height of the triable at its tallest point, then divide the product in half.

A = 1/2 x b x h, where b is the base, and h is the height.

<span>Plug your values into the formula to find the area. </span>

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dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
f(x) = |x|+5
= > x = -5 (1)

= > x = 5 (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. R{f(x)eR  [f(x) < 5} is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

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4 years ago
4 question in one 65 points
jeka94

Q6.

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have: slope m = 3, y-intercept (0, 4) → b= 4

<h3>Answer: y = 3x + 4</h3>

Q7.

2x + 4y = 4     |subtract 2x from both sides

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y = -0.5x + 1

Only second graph has y-intercept = 1.

<h3>Answer: The second graph.</h3>

Q8.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have

(-16,\ 8)\to x_1=-16,\ y_1=8\\(4,\ -2)\to x_2=4,\ y_2=-2

Substitute:

m=\dfrac{-2-8}{4-(-16)}=\dfrac{-10}{20}=-\dfrac{1}{2}\\\\y-8=-\dfrac{1}{2}(x-(-16))\\\\y-8=-\dfrac{1}{2}(x+16)

<h3>Answer: The first equation.</h3>

Q9.

It's a vertical line. The equation of a vertical line is x = <em>a</em>, where <em>a</em> is any real number.

<h3>Answer: x = -4</h3>
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Answer:

i think that the correct answer is a

Step-by-step explanation:

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