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Gala2k [10]
2 years ago
10

The average profit a local store owner earns on a given day is $550 and is growing exponentially at a rate of 60% per year. Writ

e a function to represent profit after t years, where the daily rate of change can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage rate of change per day, to the nearest hundredth of a percent.
Mathematics
1 answer:
sashaice [31]2 years ago
7 0

The exponential function used to represent the profit after t years is y=550(1.6)^t

<h3>Exponential function</h3>

An exponential function is in the form:

y = abˣ

where y, x are variables, a is the initial value of y, and b is the multiplier.

Let y represent the profit after t years.

Since the profit on a given day is $550 and is growing exponentially at a rate of 60% per year. Hence:

  • a = 550
  • b = 100% + 50% = 1.6

The profit function is given by:

  • y=550(1.6)^t

The exponential function used to represent the profit after t years is y=550(1.6)^t

Find out more on exponential function at: brainly.com/question/12940982

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Step-by-step explanation:

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3 years ago
Find the prime factorizations foor the following numbers 36 and 84
Varvara68 [4.7K]
Answer:

36 = 2² * 3²
84 = 2² * 3 * 7


Explanation:

Pf of 36 = 2 * 2 * 3 * 3 which then becomes 2 (to the power of 2) times 3 (to the power of 2)

Pf of 84 = 2 * 2 * 3 * 7 which then becomes 2 (to the power of 2) * 3 * 7

If this helps it would be greatly appreciated if you thanked me.
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3 years ago
You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building
nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

h=\sqrt{x^2+y^2}

The rate of change for the distance between you and the elevator is given by:

\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}

-16=\frac{dh}{dy}*\frac{dy}{dt}

\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\

Applying the chain rule:

u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}

Therefore, at x=300 and y = 500, dy/dt is:

-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s

The elevator is descending at 18.66 ft/s.

7 0
3 years ago
Please only answer if you know the answer!!!
ExtremeBDS [4]

Answer:

y=3x

Step-by-step explanation:

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5 0
3 years ago
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myrzilka [38]

Answer:

Distance= 6.6 miles

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Let's determine angle b first

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Using cosine rule

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X² =8.8²+2.4²-2(8.8)(2.4)cos20

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X= √43.51

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Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
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