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3 years ago

Solve the system by either elimination or substitution

1 answer:

5 0

The correct answer is A: x=2 and y=-3. Either method would work, but for example, let's use elimination. If you multiply the second equation by 5, you get: 10x +5y = 5. When you add both equations, you can then cross out both y terms. You are left with one equation that reads: 13x=26. Solving for x gives you 2. You can substitute 2 in for x in either equation and you will receive -3 for your y value.

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Can you help me with this problem

snow_lady [41]

Since there are no actual values, I guess we just have to isolate the b.

2A=bh (multiply both sides by 2)
2A/h=b (divide by h)

hope this helps

4 0

3 years ago

Find all real solutions:<br> x² - x - 12 = 0

Andrej [43]

Factor the equation. Remember the value should add to the b value and multiply to the c value.

x^2-x-12= 0
(x-4)(x+3)=0

Use the zero product property to find roots
x-4=0
x=4

x+3=0
x=-3

Final answer: x=-3, x=4

8 0

3 years ago

Whatttttt? Help meeeeeeeeeeeeeeeeeeeeeeeee... lost all braincells binge watching peppa!!!

morpeh [17]

Answer: C

Step-by-step explanation: It's the most logical.

and don't lie. We all know you watch dora more.

5 0

3 years ago

Read 2 more answers

EFGH is a parallelogram. Find the measure of EG.

gayaneshka [121]

Answer: 64

Step-by-step explanation:

If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.

EJ = JG

4w + 4 = 2w + 18

Subtract 2w from both sides

2w + 4 = 18

Subtract 4 from both sides

2w = 14

Divide both sides by 2

w = 7

EG = EJ + JG

EG = 4w + 4 + 2w + 18

EG = 6w + 22

Now that we know what 'w' is, we can substitute it for 7

EG = 6 (7) + 22

EG = 42 + 22 = 64

The measure of EG is 64.

Hope that helped!

7 0

3 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago