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pentagon [3]
3 years ago
5

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits w

hich is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 28.0 ∘ from the centerline?
Physics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

∅=2021rad

Explanation:

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) i the light from the two slits at an angle of 28.0 ∘ from the centerline?

A wave is a disturbance which travels through a medium, it transfers energy without a permanent displacement of the medium itself. this is an example of light wave

using the formula below

∅=\frac{2\pi*d }{\beta } sin\alpha

the phase difference is given from the above

d= distance/separation of slits .00037m

\beta=wavelength

540*10^-9m

\alpha=angle of two slits  28.0 ∘

∅=(\frac{2\pi*0.00037 }{540*10^-9} sin 28

∅=2021rad

there are large bright fringes from the centre line

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