Question

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 28.0 ∘ from the centerline?

Answer 1

Answer:

∅=2021rad

Explanation:

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) i the light from the two slits at an angle of 28.0 ∘ from the centerline?

A wave is a disturbance which travels through a medium, it transfers energy without a permanent displacement of the medium itself. this is an example of light wave

using the formula below

∅=$\frac{2\pi*d }{\beta } sin\alpha$

the phase difference is given from the above

d= distance/separation of slits .00037m

$\beta$=wavelength

540*10^-9m

$\alpha$=angle of two slits  28.0 ∘

∅=($\frac{2\pi*0.00037 }{540*10^-9} sin 28$

∅=2021rad

there are large bright fringes from the centre line