Moving 2.0 coulombs of charge a distance of 6.0 meters from point A to point B within an electric field requires a 5.0-newton fo
rce. What is the electric potential difference between points A and B?
1 answer:
Answer:
15 V
Explanation:
Electric potential is given as the product of Electric field and distance. Mathematically:
V = E * r
Where E = Electric field
r = distance = 6m
Electric field, E, is:
E = F / q
Where F = Electric force = 5N
q = Electric charge = 2C
Therefore, electric potential will be:
V = (F * r) / q
V = (5 * 6) / 2
V = 15V
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