Ask question

Ask question

All categories

4 years ago

9

The manipulated variable is plotted on the horizontal axis

1 answer:

tatuchka [14]4 years ago

8 0

<span>True.

Manipulated variable or also called the controlled variables are variables in which you regulate. Manipulate or as said control. By this you want to certain the outcome of a certain experiment. Making it close to which you want it or desired it to be, possibly. Characteristics could be: </span>
<span><span>1.       </span>You are able to have govern or a certain variable is controllable.</span> <span><span>
2.       </span>The outcome or effect of a particular variable was what you were determining or were testing with high probability</span>
<span><span>3.       </span>You can either increase or decrease the level of which the variable could take effect on a dependent variable.<span>
</span></span>

You might be interested in

An argument against the validity of evolutionary theory says that there are too few transitional forms representing the gap betw

ICE Princess25 [194]

Answer:They both relate in that almost every specie in the pre-mordern human fossil record can be deregarded as a transitional specie between the African Ape and the modern man.

Explanation:

6 0

3 years ago

If there is an unusually windy month one might anticipate a. Higher tides b.increased wave size c. Unpredictable currents d. Low

Luden [163]

I belive it is b. increased wave size

6 0

3 years ago

For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _________ diopters A) 1.08 diopters

natita [175]

Answer:

The power of lens is 2.22 D.

Explanation:

Given that,

Distance of image v= 45 cm

We know that,

Distance of object u= ∞

Power of lens is the reciprocal of focal length.

$P=\dfrac{1}{f}$

We need to calculate the power of lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

Where, f = focal length

v = image distance

u = object distance

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{45}+\dfrac{1}{\infty}$

$\dfrac{1}{f}=\dfrac{1}{0.45}+0$

$P=\dfrac{1}{f}=2.22$

Hence, The power of lens is 2.22 D.

7 0

3 years ago

A flea jumps by exerting a force of 1.09 ✕ 10−5 N straight down on the ground. A breeze blowing on the flea parallel to the grou

patriot [66]

Answer:

a= 17.877 m/s² : Magnitude of the acceleration of the flea

β = 88.21° : Direction of the acceleration of the flea

Explanation:

Conceptual analysis

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Problem development

Look at the flea free body diagram in the attached graphic

The acceleration is presented in the direction of the resultant force (R) applied over the flea .

$R= \sqrt{(F_{x})^{2} + (F_{y})^{2} }$

$R= \sqrt{(10.9)^{2}+(0.340)^{2} } *10^{-6} N$

R= 10.905*10⁻⁶ N

We apply the formula (1) to calculate the magnitude of the acceleration of the flea

∑F = m*a m = 6.1 * 10⁻⁷ kg

R = m*a

a= R/m

a= (10.905*10⁻⁶) / (6.1 * 10⁻⁷ )

a= 17.877 m/s²

β: Direction and magnitude of the acceleration of the flea

$\beta = tan^{-1} (\frac{F_{y} }{F_{x} } )$

$\beta = tan^{-1} (\frac{10.9*10^{-6} }{0.340*10^{-6} } )$

β = 88.21°

5 0

4 years ago

Sound source A is located at x = 0, y = 0, and sound source B is located at x = 0, y = 2.3 m. The two sources radiate coherently

Oliga [24]

Answer:

Solution is given in the attachments

4 0

3 years ago