Question

Factor the trinomial below.

Answer 1

Answer:

C.  3(2x+1)(x-2)

Step-by-step explanation:

To factor the trinomial 6x² - 9x -6, we will follow the steps below;

First, 3 is common among the three numbers, so we will start by factoring out 3, so that the expression becomes;

3(2x² -  3x - 2)

We will now proceed to factorize; 2x² -  3x - 2  

Find two numbers such that its product gives -4 and its sum gives -3.

Such number is -4 and 1

-4 × 1 = -4

-4 + 1 = -3

We will replace -3x by -4x + x in the above expression

2x² -  4x + x - 2

(2x² -  4x) (+x - 2)

In the first parenthesis, 2x is common, so we will factor out 2x while in the second parenthesis 1 is common, so we will factor out 1. Hence;

2x(x - 2)  + 1(x-2)

(2x+1)(x-2)

3(2x² -  3x - 2)  = 3(2x+1)(x-2)

6x² – 9x – 6 = 3(2x+1)(x-2)

Therefore the factorized form of 6x² – 9x – 6  is   3(2x+1)(x-2)

Answer 2

For this case we have the following trinomial:
 6x2 - 9x - 6
 Rewriting we have:
 3 (2x2 - 3x - 2)
 Factoring we have:
 3 (2x + 1) (x-2)
 Answer:
 The factored expression for this case is given by:
 C. 3 (2x + 1) (x - 2)