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3 years ago

5

Jenna took an open bowl of leftover mashed potatoes from the refrigerator. She determined that chemical changes occurred since t

he potatoes were first placed there.
Which observations most likely led to Jenna’s conclusion

1 answer:

Kamila [148]3 years ago

5 0

Answer:

maybe the potatoes took a different form? They smell different, look different taste different, etc.

Explanation:

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Svet_ta [14]

I will need a picture if the periodic table

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3 years ago

If 1000. ml of linseed oil has a mass of 929 g, calculate the density of linseed oil

Ierofanga [76]

<span>0.929 g/ml Density in this case is defined as mass per volume. Or in other words, mass divided by volume. So you simply divide 929 grams by 1000 ml. Giving 929 g / 1000 ml = 929/1000 g/ml = 0.929 g/ml</span>

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3 years ago

Tom pushes on a 50-kilogram box with a force of 25 newtons. Assuming the surface on which the box moves is frictionless, at what

zhannawk [14.2K]

Assuming the surface on which the box moves is frictionless, the rate at which the box accelerate is equal to 0.5 $m/s^2$ .

<u>Given the following data:</u>

Mass of box = 50 kilogram

Force = 25 newtons.

To determine the rate at which the box accelerate, assuming the surface on which the box moves is frictionless:

Mathematically, Newton's Second Law of Motion is given by the formula;

$Force = mass \times acceleration$

Making acceleration the subject of formula, we have:

$Acceleration =\frac{Force}{mass}$

Substituting the given parameters into the formula, we have;

$Acceleration = \frac{25}{50}$

Acceleration = 0.5 $m/s^2$

Read more on Newton's Law of Motion here: brainly.com/question/1121817

3 0

2 years ago

The dissociation of calcium carbonate has an equilibrium constant of Kp= 1.20 at 800°C. CaCO3(s) ⇋ CaO(s) + CO2(g)

Fed [463]

Explanation:

(a) Formula that shows relation between $K_{c}$ and $K_{p}$ is as follows.

$K_c = K_p \times (RT)^{-\Delta n}$

Here, $\Delta n$ = 1

Putting the given values into the above formula as follows.

$K_c = K_p \times (RT)^{-\Delta n}$

= $1.20 \times (RT)^{-1}$

= $\frac{1.20}{0.0820 \times 1073}$

= 0.01316

(b) As the given reaction equation is as follows.

$CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)$

As there is only one gas so ,

$p[CO_{2}] = K_{p}$ = 1.20

Therefore, pressure of $CO_{2}$ in the container is 1.20.

(c) Now, expression for $K_{c}$ for the given reaction equation is as follows.

$K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}$

= $\frac{x \times x}{(a - x)}$

= \frac{x^{2}}{(a - x)}[/tex]

where, a = initial conc. of $CaCO_{3}$

= $\frac{22.5}{100} \times 9.56$

= 0.023 M

0.0131 = $\frac{x^{2}}{0.023 - x}$

x = 0.017

Therefore, calculate the percentage of calcium carbonate remained as follows.

% of $CaCO_{3}$ remained = $(\frac{0.017}{0.023}) \times 100$

= 75.46%

Thus, the percentage of calcium carbonate remained is 75.46%.

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4 years ago

In June there are fewer hours of daylight and less direct sunlight in the

Dafna11 [192]

<span>In June there are fewer hours of daylight and less direct sunlight in the Southern Hemisphere.

Your answer is <em>Southern Hemisphere</em><em></em>.

</span>

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3 years ago