At constant temperature and pressure, the coefficients for gaseous species in a valences chemical reaction can be interpreted as
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Moles of O₂ = 3.92
<h3>Further explanation</h3>Given
V=1 L
T=-118 °C + 273 = 155 K
P = 49.77 atm
Required
moles of O₂
Solution
the gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
Input the value :
n= PV/RT