Ask question

Ask question

All categories

3 years ago

11

PLEASE HELP FILL OUT THIS CHART! ASAP THANK YOU

1 answer:

Svet_ta [14]3 years ago

6 0

I will need a picture if the periodic table

You might be interested in

Your experiment requires 150 mL of 7.7 M NaOH. How many grams of NaOH will you need?

Elodia [21]

You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L) to get the solution.
150 ml= .150 L
7.7 = N/.150
N=.1.155 moles of NaOH.
And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (1.155mol) =
46.2 g of NaOH.</span>

7 0

3 years ago

Please,help me in question number 2 and 4.<br><img src="https://tex.z-dn.net/?f=2and4%20%5C%5C%20" id="TexFormula1" title="2and4

svetoff [14.1K]

I think it’s 890 I really don’t know

8 0

3 years ago

The metal content of iron in ores can be determined by a redox procedure in which the sample is first oxidized with Br2 to conve

coldgirl [10]

Answer:

80.27%

Explanation:

Let's consider the following balanced equation.

2 Fe³⁺(aq) + Sn²⁺(aq) ⇒ 2Fe²⁺(aq) + Sn⁴⁺(aq)

First, we have to calculate the moles of Sn²⁺ that react.

$\frac{0.1015molSn^{2+} }{1L} .13.28 \times 10^{-3} L=1.348\times 10^{-3}molSn^{2+}$

We also know the following relations:

According to the balanced equation, 1 mole of Sn²⁺ reacts with 2 moles of Fe³⁺.
1 mole of Fe³⁺ is oxidized from 1 mole of Fe.
The molar mass of Fe is 55.84 g/mol.

Then, for 1.348 × 10⁻3 moles of Sn²⁺:

$1.348\times 10^{-3}molSn^{2+}.\frac{2molFe^{3+} }{1molSn^{2+} } .\frac{1molFe}{1molFe^{3+} } .\frac{55.84gFe}{1molFe} =0.1505gFe$

If there are 0.1505 g of Fe in a 0.1875 g sample, the mass percentage of Fe is:

$\frac{0.1505g}{0.1875g} \times 100 \% = 80.27\%$

5 0

4 years ago

Saturated hydrocarbon molecules may be bonded in which type of structure?

poizon [28]

<span>all of the above can be saturated molecules </span>

3 0

4 years ago

Read 2 more answers

What is the correct formula for calcium phosphate?

coldgirl [10]

<span>your answer is Ca3</span>(PO4)2<span>, </span>

6 0

3 years ago