This set up of a conversion table should show you that if you multiply the grams of BeI2 times .02 moles, it equals <span>5.256 g (your answer) </span>
PLEASE HELP FILL OUT THIS CHART! ASAP THANK YOU
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seaweed having 50 g salt in 1 L water. The bucket contains 150 g of salt in 2 L of water
amount of water present in bucket is twice to amount of water in weed
At equilibrium, volume of water in weed is x and volume in bucket is y but concentration remain same as follows:
At equilibrium, weed loose z L from 1 L water to bucket containing 2 L as follows:
Thus, Weed will loose 0.25 L of water