True or False:

Physics

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

Explanation:

false because the light of some stars can be very bright, but it can also be very far from the earth.

have a nice day

mart [117]3 years ago

3 0

This is a true statement

You might be interested in

Using an example, explain how being able to understand scientific principles and think scientifically can help you solve problem

crimeas [40]

One example is that when their food catches fire in a cooking pot or pan, it is advisable to smother the fire by covering the fire with a blanket rather than douse the fire with water. DOeing the later will only aggravate the fire. Knowledge of basic science dictates that oil and water are immiscible liquids the oil will continue to burn even as the water is poured into the oil. More so, as the water violently evaporates due to the heat, it spreads the burning oil and hence spreads the fire.

7 0

3 years ago

Read 2 more answers

How do you know the speed of an electromagnetic wave in a vacuum?

ycow [4]

Electromagnetic waves need no matter to travel - they can travel through empty space (a vacuum). In a vacuum, all electromagnetic waves travel at approximately 3 x 108 m/s - which is the fastest speed possible. ...
Light traveling value through an optical Fibre is, 2 x 108 m/s. Hope that helps.

5 0

3 years ago

Which of the planets do not have moons?

lubasha [3.4K]

Answer:

Mercury and Venus

Explanation:

7 0

4 years ago

Read 2 more answers

The gravitational attraction between a 20 kg cannonball and a 0.002 kg

Naya [18.7K]

Answer:

$2.966\times 10^{-11}\ N$

Explanation:

Given:

Mass of the cannonball (M) = 20 kg

Mass of the marble (m) = 0.002 kg

Distance between the cannonball and marble (d) = 0.30 m

Universal gravitational constant (G) = $6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}$

Now, we know that, the gravitational force (F) acting between two bodies of masses (m) and (M) separated by a distance (d) is given as:

$F=\dfrac{GMm}{d^2}$

Plug in the given values and solve for 'F'. This gives,

$F=\frac{(6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2})\times (20\ kg)\times (0.002\ kg)}{(0.30\ m)^2}\\\\F=\frac{6.674\times 20\times 0.002\times 10^{-11}\ m^3 kg^{-1+2} s^{-2}}{0.09\ m^2}\\\\F=2.966\times 10^{-11}\ kg\cdot m\cdot s^{-2}\\\\F=2.966\times 10^{-11}\ N.........(1\ N = 1\ kg\cdot m\cdot s^{-2})$