Two equal-mass balls swing down and hit identical bricks while traveling at identical speeds. Ball A bounces back, but ball B ju
1 answer:
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Answer:
The true course: north of east
The ground speed of the plane: 96.68 m/s
Explanation:
Given:
= velocity of wind =
= velocity of plane in still air =
Assume:
= resultant velocity of the plane
= direction of the plane with the east
Since the resultant is the vector addition of all the vectors. So, the resultant velocity of the plane will be the vector sum of the wind velocity and the plane velocity in still air.
Let us find the direction of this resultant velocity with respect to east direction:
This means the the true course of the plane is in the direction of north of east.
The ground speed will be the magnitude of the resultant velocity of the plane.
Hence, the ground speed of the plane is 96.68 km/h.
Answer:
Impulse will be 12 kgm/sec
So option (b) will be correct option
Explanation:
We have given mass of the baseball m = 0.15 kg
Ball speed before hit
Ball speed after hitting ( negative direction due to opposite direction )
We have to find the impulse
We know that impulse is equal; to the change in momentum
So change in momentum =
So option (b) will be correct option