We can find the x-component of the force vector, so Fx = 25N(cos30). Then, we can sub this into the work equation W = Fs or W = Fd.
Therefore, W = (25N(cos30))(3m) = 64.95 J.
With sig figs, it is 60 J.
The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude <em>w</em>), the normal force (mag. <em>n</em>), and the friction force (maximum mag. <em>f</em> ).
In the horizontal direction, we have
<em>n</em> cos(120º) + <em>f</em> cos(30º) = 0
-1/2 <em>n</em> + √3/2 <em>f</em> = 0
<em>n</em> = √3 <em>f</em>
and in the vertical,
<em>n</em> sin(120º) + <em>f</em> sin(30º) + (-<em>w</em>) = 0
<em>n</em> sin(120º) + <em>f</em> sin(30º) = (50 kg) (9.80 m/s²)
√3/2 <em>n</em> + 1/2 <em>f</em> = 490 N
Substitute <em>n</em> = √3 <em>f</em> and solve for <em>f</em> :
√3/2 (√3 <em>f </em>) + 1/2 <em>f</em> = 490 N
2 <em>f</em> = 490 N
<em>f</em> = 245 N
(pointed up the incline)
Based on the chemical reaction, Carbon reacts with Oxygen would yield Carbon Dioxide, we can imply that the "<span>Atoms are always conserved during chemical reactions." It is one of the fundamental concepts in chemistry wherein the mass is always conserved in a reaction since it can't be created nor destroyed.</span>
Answer:
Option A
The drag force goes up by a factor of 4
Explanation:
Fact:
Drag force is directly proportional to the square of the velocity of a moving object
Therefore, when drag force pushes opposite to the motion as one rides a bicycle, the magnitude of drag force increases by a factor of 4
Density is equal to mass divided by volume; that said, you would divide 38.6 by 2 to get your answer
