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3 years ago

If 3,600 J of work is done in 3.0 s, what is the power?

Physics

2 answers:

CaHeK987 [17]3 years ago

6 0

The power when 3600 J is done in 3 secs is 1200W

zlopas [31]3 years ago

6 0

What's the answer choices?

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A 90.0 kg man climbs hand over hand up a rope to a height of 9.47 m. How much potential energy does he have at the top?

kati45 [8]

Answer:

8361.063 J

Explanation:

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2 years ago

During a solar eclipse, which of the following is true?

kaheart [24]

Answer:

The Moon blocks the suns light from hitting the surface of the earth

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2 years ago

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9. A soft drink distibutor drove west 11 km from Minnehaha to Nut Plains. She then turned around and drove back east for 209 km

guajiro [1.7K]

Answer:

220km

Explanation:

Given parameters:

Distance traveled from Minnehaha to Nut Plains = 11km

Distance traveled to Dover = 209km

Unknown:

The distance the soft drink distributor traveled = ?

Solution:

To solve this problem, we must understand that distance is the total length of path covered in a journey.

So;

Distance = 209km + 11km = 220km

The soft drink distributor covered 220km

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2 years ago

A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long

KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

$h=Lsin30$

$h=10sin30$

$h=5m$

In the case of Inertia would be given by

$I = \frac{mR^2}{2}$

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

$I = mk^2$

$\frac{mR^2}{2}= mk^2$

$\frac{k^2}{R^2}=\frac{1}{2}$

Replacing in Energy conservation Equation we have that

Potential Energy = Kinetic Energy of Rolling Object

$mgh = \frac{1}{2}mv^2(1+\frac{k^2}{r^2})$

$9.8*5=\frac{1}{2}v^2(1+\frac{1}{2})$

$v^2 (1.5) = 98$

$v=8.0829m/s$

Therefore the correct answer is C.

3 0

3 years ago

When a snowball turns into a puddle of

In-s [12.5K]

When a snowball turns into a puddle of water, we know that (the snow ball gains energy and changes from a solid to liquid).

This is correct due to the fact that particles of the snowball are gaining speed and so it is heating up, when the solid's temperature reaches the melting point, it will become a liquid.

Therefore, D is the correct answer.

8 0

2 years ago