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borishaifa [10]
3 years ago
7

How many milliliters of 0.60 H₂SO₄ are required to neutralize 90 mL of 0.40 NaOH?

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

The answer to your question is 30 ml of H₂SO₄

Explanation:

Data

the volume of H₂SO₄ = ?

[H₂SO₄] = 0.6 M

volume of NaOH = 90 ml

[NaOH] = 0.4

Process

1.- Write the balanced chemical equation

             H₂SO₄  +  2NaOH  ⇒  Na₂SO₄  +  2H₂O

2.- Calculate the moles of NaOH

Molarity = moles/volume

moles = Molarity x volume

-Substitution

moles = 0.4 x 0.09

-result

moles = 0.036 of NaOH

3.- Calculate the moles of H₂SO₄

            1 mol of H₂SO₄ ---------------- 2 moles of NaOH

             x                      ----------------- 0.036 moles of NaOH

                   x = (0.036 x 1)/2

                   x = 0.018 moles of H₂SO₄

4.- Calculate the volume of H₂SO₄

Volume = moles / Molarity

-Substitution

Volume = 0.018 / 0.6

-Result

Volume = 0.03 ml or 30 ml

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3 years ago
A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0
4 years ago
Weight of one mole of carbon = 12.01 g Weight of one mole of oxygen = 16.00 g The molecular weight (gram formula weight) for CO
murzikaleks [220]

Answer:

28.01g

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Given the weight of one mole of Cabon as 12.01g and that of oxygen as 16.00g.

The molecular weight of a compound can be gotten by adding the molar weights of the elements that constitutes the compound .

The molecular weight of the compound CO is therefore

equal to the sum of the weight of both elements.

That’s = 12.01g + 16.00g

= 28.01g

Therefore, the molecular weight of CO is 28.01g

4 0
4 years ago
Why does a solid change to a liquid when heat is added
Nata [24]
Particles will have more energy and will vibrate really fast.

(Hope this helps)
4 0
3 years ago
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