NH3 forms a basic solution of ammonium hydroxide.
<span>NaCL - no it is a salt. Salts are generally inert. </span>
<span>H2O - no, it is both an acid and base, but because of this it has neutralized itself and is also inert. </span>
<span>HNO3 - yes. It is a strong acid and forms the salt ammonium nitrate. </span>
<span>Ca(OH)2 - no, it is another base. Bases react with acids.
your answer is HNO3</span>
CIO4-=-1
CI=4O=-1
O has a 2- oxidation change so
CI+4(-2)=-1
CI+(-8)=-1
CI=-1+8=7
So the oxidation number of chlorine is 7 in this case
Density is sensitive to temperature for gases and liquids, although not much for liquids. We use the data in the picture. Using linear interpolation, we determine the densities at 14°C and 20°C.
@20°C: Density = 0.99823 g/cm³ or g/mL
@14°C:
(10 - 14)/(10 - 20) = (0.99973 - Density)/(0.99973 - 0.99823)
Solving for density:
Density = 0.99913 g/cm³ or g/mL
Mass @ 20°C = 50 mL * 0.99823 g/mL = 49.9115 g
Mass @ 14°C = 50 mL * 0.99913 g/mL = 49.9565 g
Difference of Masses = |49.9115 g - 49.9565 g| = 0.045 g
<span>Cadmium Permanganate
Cd - Cadmium
Mn - Manganese
O - Oxygen (-ate)
Hope this helps!
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Answer:
i think its changing shape if I'm wrong I'm sorry