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2 years ago

11

In the titration of a solution of Sodium hydroxide, an acid titrant was prepared by diluting 125.0 mL of 10.00 mol/L Nitric acid

into enough distilled water to make 500.0 mL of solution. 30.0 mL of the base was measured, and in the titration, 16.74 mL of the acid titrant was needed to neutralize. Determine the concentration of the Sodium hydroxide.

1 answer:

harina [27]2 years ago

6 0

Answer:

1.395M NaOH

Explanation:

Sodium hydroxide, NaOH, reacts with nitric acid, HNO3, as follows:

NaOH + HNO3 → NaNO3 + H2O

<em>Where 1mol of NaOH reacts with 1mol of HNO3</em>

To solve this question we must find the concentration of the titrant. With the concentration and the needed acid we can find the moles of HNO3 added = moles NaOH in the solution. With the moles of NaOH and its volume we can find its concentration as follows:

<em>HNO3 concentration:</em>

10.00mol/L HNO3 * (125.0mL/500.0mL) = 2.500M HNO3

<em>Moles HNO3 = Moles NaOH:</em>

16.74mL = 0.01674L*(2.500mol/L) = 0.04185 moles HNO3 = Moles NaOH

<em>Concentration NaOH:</em>

0.04185 moles / 0.0300L =

1.395M NaOH

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