Answer:
quoted, but you can learn from this.
Explanation:
"The different types of microscopes are all necessary because not all experiments require the same level of magnification.<em> [ For dissections low magnification is sufficient, so a dissecting microscope works very well, while for viewing single cells the 1000 fold magnification of a compound light microscope is more than adequate. ] " </em>
Answer:
When a sodium atom transfers an electron to a chlorine atom, forming a sodium cation (Na+) and a chloride anion (Cl-), both ions have complete valence shells, and are energetically more stable. The reaction is extremely exothermic, producing a bright yellow light and a great deal of heat energy.
A base tastes bitter, while an acid tastes sour.
Answer: Base
Answer:
4050 mL
Explanation:
Given data:
Mass of glucose = 150.1 g
Molarity of solution = 0.205 M
Volume of solution = ?
Solution:
Molarity = number of moles of solute / L of solution.
Now we will calculate the moles of sugar first.
Number of moles = mass/ molar mass
Number of moles = 150.1 g/ 180.156 g/mol
Number of moles = 0.83 mol
Now we will determine the volume:
Molarity = number of moles of solute / L of solution.
0.205 M = 0.83 mol / L of solution.
L of solution = 0.83 mol / 0.205 M
L of solution = 4.05 L
L to mL conversion:
4.05 L × 1000 mL / 1 L = 4050 mL
Answer:
The moles of sucrose that are available for this reaction is 0.0292 moles
Explanation:
Combustion is an specifyc reaction where the reactants react with O₂ in order to produce CO₂ and H₂O
This combustion is: C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O
We have to conver the mass to moles, to find out the limiting reactant
10 g . 1 mol / 342 g = 0.0292 moles of sucrose
8 g . 1mol / 32g = 0.250 moles of O₂
The moles of sucrose that are available for this reaction is 0.0292 moles
Before we start to work with the equation we must find the limiting reactant. When you find it, you can do all the calculations.
