Answer:
Q=25.7 Kj
Explanation:
76.941 g H2O*1 mol/18.016= 4.27 Mol H20
(4.27 Mol H2O)(6.009 Kj/Mol)
Q=25.7 Kj
Explanation:
The balanced chemical equation of the reaction is:

From the balanced chemical equation,
1 mole of propane forms ------ 3 mol. of
gas.
The molar mass of propane is 44.1 g/mol.
One mole of any gas at STP occupies --- 22.4 L.
Hence, 44 g of propane forms (3x22.4 L=) 67.2 L of CO2 gas at STP.
Answer:
Thus, 67.2 L of CO2 is formed at STP.
Nitrogen in the limiting reactant x