74) A solution is prepared by dissolving 0.60 g of nicotine (a nonelectrolyte) in water to make 12 mL of solution. The osmotic p
1 answer:
Answer:
molar mass of nicotine will be 162.16g/mol
Explanation:
The mass of nicotine taken = 0.60g
The volume of solution = 12mL
the osmotic pressure of solution = 7.55 atm
Temperature in kelvin =298.15K (25+ 273.15)
The formula which relates osmotic pressure and concentration (moles per L) is:
π = MRT
Where
π = osmotic pressure (unit atm) = 7.55 atm
M = molarity (mol /L)
T= temperature = (K) = 298.15 K
R = gas constant = 0.0821 L atm /mol K
Putting values
Therefore
Molarity is moles of solute dissolve per litre of solution
The volume of solution in litre = 0.012 L
we know that
molar mass =
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Answer:
Rate = k . [B]² . [C]
Explanation:
The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.
where,
k is the rate constant
x, y, z are the reaction orders.
- <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
- <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
- The rate of the reaction is linearly dependent on the concentration of C. This means that the reaction order for C is z = 1, that is, a linear dependence.
All in all, the rate equation is:
Rate = k . [B]² . [C]
Explanation:
The given data is as follows.
Concentration of solution = 0.5 M
Volume of solution = 1 L
Molar mass of Glycylglycine = 132.119 g/mol
As molarity is the number of moles present in liter of solvent.
Mathematically, Molarity =
Hence, calculate the number of moles as follows.
No. of moles = Molarity × Volume
=
= 0.5 mol
Therefore, mass of glycylglycine = mol × molar mass
=
= 66.06 g
Thus, we can conclude that 66.06 g glycylglycine is required.
Answer: Oxygen is the limiting reagent.
Explanation:
As can be seen from the given balanced equation:
3 moles of reacts with 1 mole of
1.52 moles of reacts with=
of
Thus is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of
will remain as such and thus
is an excess reagent.