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mojhsa [17]
3 years ago
7

A company desires to produce nickel from refining nickel oxide and sulfide ores. the first step of the process will produce a ni

ckel carbonyl gas ni(co)4 by heating the ore. the second step is as follows: ni(co)4(
g. ni(s) + 4co(
g. how would you accelerate the production of ni? select all that apply. reduce the concentration of nico4 increase the concentration of nico4 withdraw co from the products as it is forming adding co to the reaction
Chemistry
1 answer:
inn [45]3 years ago
4 0
Answer is: increase the concentration of NiCO₄ and <span>withdraw CO from the products as it is forming.

Balanced chemical reaction: NiCO</span>₄(g) ⇄ Ni(s) + 4CO(g).
According to Le Chatelier's Principle the position of equilibrium moves to counteract the change:
1) the position of equilibrium will move to the right, so that the concentration of nickel carbonyl gas decreases again and produce more nickel.
2)  the position of equilibrium will move to the right, if we decrease concentration of carbon monoxide, more nickel carbonyl gas will decompose and produce more nickel.

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Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?
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Equilibrium expression is Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is  the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

Therefore, Equilibrium expression is Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

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2 years ago
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