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yaroslaw [1]
3 years ago
11

A bag of chocolates is labeled to contain 0.384 pound of chocolates. The actual weight of the chocolates is 0.3798 pound. Are th

e chocolates heavier or lighter than the weight stated on the label? Explain how you know.
Mathematics
2 answers:
siniylev [52]3 years ago
7 0
The actual weight of the chocolate is a small bit less than the weight stated on the bag. I know this because 0.384 is heavier than 0.3798 due to the number in the hundreds place being larger.
taurus [48]3 years ago
5 0

Answer:

The answer to your question is the chocolates are slightly lighter than the weight stated on the label.

Step-by-step explanation:

Data

The label says 0.384 pounds

Actual mass = 0.3798 pounds

Process

To solve this problem the only thing we must do is substrate the actual weight of chocolates to the weight of chocolates stated on the label.  

If the result is positive, then the chocolates are lighter  

If the result is negative, then the chocolates are heavier

          0.384 pounds - 0.3798 pounds = 0.0042

hmu if you need sumin els!

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Step-by-step explanation:

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Answer:

Joanna bought 21 items that come out to a total of $33.33. She bought 9 notebooks and 12 pencils.

Step-by-step explanation:

Notebooks (N) = $1.85 Pencils (P) = $1.39

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3 years ago
Write an equation of the line, in standard form, containing the points (−6, 19) and (−15, 28).
Rudiy27

The equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13

<em><u>Recall:</u></em>

  • Equation of a line can be written in standard from as Ax + By = C, where Ax and By are all terms of variable x and y, and C is a constant.
  • The equation of a line in point-slope, y - y_1 = m(x - x_1), can be rewritten in the standard form.
  • Slope (m) = \frac{y_2 - y_1}{x_2 - x_1}

Given: (−6, 19) and (−15, 28)

<em>Find the </em><em>slope </em><em>(m):</em>

<em />m = \frac{28 - 19}{-15 -(-6)} = \frac{9}{-9} = -1

Write the equation in point-slope form by substituting m = -1 and (x_1, y_1) = (-6, 19) into y - y_1 = m(x - x_1).

y - 19 = -1(x - (-6))\\\\y - 19 = -1(x + 6)

  • Rewrite in standard form

y - 19 = -1(x + 6)\\\\y - 19 = -x - 6\\\\y = -x - 6 + 19\\\\y = -x + 13\\\\\mathbf{x + y = 13}

Therefore, the equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13

Learn more about equation of a line in standard form on:

brainly.com/question/19169731

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