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musickatia [10]
3 years ago
11

Which relationship or statement best describes delta s for the following reaction:

Chemistry
1 answer:
zalisa [80]3 years ago
4 0

Answer:

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).

  • If Δn(g) > 0, the entropy increases (ΔS > 0).
  • If Δn(g) < 0, the entropy decreases (ΔS < 0).
  • If Δn(g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)

Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.

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Calculate the molarity when 135 g of KCl is dissolved to make a 2.50 L solution. Round to two significant digits.
inysia [295]
<h2>0.72 mol/L</h2>

Explanation:

       \textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}

       We are given a 2.50L solution which contains 135g of KCl.

       To calculate number of moles of KCl present, we need to find it's molar mass from charts. Molar Mass of KCl is known to be 74.55\frac{g}{Mol}.

       Number of moles of KCl present = \frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol

       Molarity = \frac{1.81087mol}{2.50L}=0.7243\frac{mol}{L}

∴ Molarity of given KCl solution = 0.72\frac{mol}{L}

7 0
3 years ago
A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0
miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

Q_{metal} - Q_{water} = 0

Q_{metal} = Q_{water}

Where:

Q_{water} - Heat received by water, measured in joules.

Q_{metal} - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})

The specific heat of the metal is cleared within equation above:

c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}

If we know that m_{water} = 0.237\,kg, m_{metal} = 0.244\,kg, c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}, T_{w,o} = 10\,^{\circ}C, T_{m,o} = 100.10\,^{\circ}C and T = 15.30\,^{\circ}C, the specific heat of molybdenum is:

c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}

c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

5 0
3 years ago
An example of binary compound is
Dima020 [189]

Answer:

Explanation:

An example of binary compund is ZnI2 is zinc iodide

4 0
3 years ago
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Lipids are made up of long hydrocarbon chains, composed of all carbon and hydrogen atoms. this characteristic makes lipids insol
Airida [17]
This is because their tails are hydrophobic and their heads are hydrophilic. Hydrophobic meaning dislikes being near water and hydrophilic meaning likes to be near water. Therefore, they will orientate themselves in such a manner that the heads are facing externally and all the tails are facing together protected by the hydrophilic heads. google a photo of lipid chains in water if you are still confused. I'm not sure if that is what you are asking, but I hope it helps.
8 0
3 years ago
Does the moon make its own light? Explain.
-Dominant- [34]

Answer:

No moon has no light.

Explanation:

It only reflects the light coming from the sun. Only star produces light and moon is a satellite that revolvs around the earth.

5 0
3 years ago
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