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vfiekz [6]
3 years ago
7

2000 joules are required to heat 125 grams of an unknown substance from 10 c to 28 c. What is the specific heat of the substance

?

Chemistry
1 answer:
Delicious77 [7]3 years ago
3 0
Hello! Specific heat is the amount of energy required by known amount of substance to raise its temperature by one degree celsius. In our question it is given that 2000J energy when supplied to 125 g of unknown substance raised its temperature by 18 oC. So, The specific heat is calculated as follow;

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Determine the number of molecules present in 5.60 mol of nitrogen dioxide, the number of atoms of oxygen, and the number of nitr
vaieri [72.5K]
Nitrogen dioxide is NO2 (where the number 2 is a subscript that indicates the number of atoms in one molecule).

Use Avogadro's number: 1 mol of molecules = 6.022 * 10^ 23 molecules.

So, in 5.6 mol of NO2 there are 5,6 mol * 6.022 * 10^23 molecules / mol = 33.72 * 10^23 molecules = 3.372 * 10^24 molecules of NO2.

There are the same number of N atoms (because there is 1 atom of N in 1 molecule) and there are the double of O atoms (becasue there are 2 atoms of O in 1 molecule) => 3.372 * 10 ^24 atomsof N and 6.744 atoms of O.

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3 years ago
A. Metal ion can be pushed out of position B. Metal form covalent bond C. Metals are brittle
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4 0
3 years ago
List four types of molecules important for cell processes
Fiesta28 [93]

Answer:

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2. Carbohydrates

3. Lipids

4. Nucleic Acids

Explanation:

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6 0
3 years ago
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A gas sample of 5 moles, has a volume of 95 L. How many moles of the same gas should I add to obtain a volume of 133 L at the sa
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4 0
3 years ago
An ideal gas is kept in a 10​-liter ​[L] container at a pressure of 2.5 atmospheres​ [atm] and a temperature of 310 kelvin​ [K].
Hatshy [7]

Answer:

5 L.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 10 L

Initial pressure (P1) = 2.5 atm

Final pressure (P2) = 5 atm

Final volume (V2) =.?

Since the temperature is constant, we shall apply the Boyle's law equation to determine the new volume of the gas. This can be obtained as follow:

P1V1 = P2V2

2.5 × 10 = 5 × V2

25 = 5 × V2

Divide both side by 5

V2 =25/5

V2 = 5 L

Thus, the new volume of the gas is 5 L

8 0
2 years ago
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