The value of X is 2
The total amount of sample taken is 2.00 g
The amount of sample left in the oven after drying is 1.565g
The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven
= 2.00 - 1.565
= 0.435 grams
The moles of anhydrous salt present in the hydrate = 1.565g/129.83g/mol = 0.01205
The moles of water present in the hydrate = 0.4350g/18.01g/mol = 0.02415
Therefore the ratio of these two are in 1:2 ratio
The complete chemical reaction is CoCl2.2H20
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Sodium-22 remain : 1.13 g
<h3>Further explanation
</h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually, radioactive elements have an unstable atomic nucleus.
General formulas used in decay:
![\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cbold%7BN_t%3DN_0%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7BT%2Ft%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7D)
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
half-life = t 1/2=2.6 years
T=15.6 years
No=72.5 g
![\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g](https://tex.z-dn.net/?f=%5Ctt%20Nt%3D72.5.%5Cdfrac%7B1%7D%7B2%7D%5E%7B15.6%2F2.6%7D%5C%5C%5C%5CNt%3D72.5.%5Cdfrac%7B1%7D%7B2%7D%5E6%5C%5C%5C%5CNt%3D1.13~g)
Answer: D. CYTOKINESIS
Explanation:
Mitosis<em> </em>ends<em> with telophase, or the stage at which the chromosomes reach the poles. ... Telophase is followed by </em>CYTOKINESIS<em>, or the division of the cytoplasm into two daughter </em><em>cells.</em>