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3 years ago

What is the mass, in grams, of a 12.0cm³ sample of aluminum? The density of aluminum is 2.70g/cm³

Chemistry

1 answer:

Levart [38]3 years ago

4 0

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of aluminum = 12 cm³

Density = 2.70 g/cm³

The mass of aluminum is

mass = 2.7 × 12

We have the final answer as

Hope this helps you

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QUESTION TWO

igomit [66]

Answer: The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century. It involves careful observation, applying rigorous skepticism about what is observed, given that cognitive assumptions can distort how one interprets the observation.

Explanation:

Hope this helps. :)

3 0

3 years ago

A 13 g sample of P4010 contains how many

Alex777 [14]

Answer:

$\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}$

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅, then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

$\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}$

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

$\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}$

3. Molecules of P₂O₅

$\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}$

6 0

3 years ago

What kind of simple machine is a shovel

Minchanka [31]

I think a shovel is a wedge simple machine.

8 0

3 years ago

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Be sure to answer all parts. One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, whic

KIM [24]

Answer:

The answer is below

Explanation:

one gallon of gasoline produces 9.50 kg of carbon.

The total number of cars = 40 million

Distance covered by each car = 7930 miles

Consumption rate of the cars per miles traveled is 23.6 miles per gallon.

Hence the annual gasoline consumption by all the cars in the United States of America = (total number of cars × Distance covered by each car) ÷ Consumption rate of the cars per miles

annual gasoline consumption by all the cars = (40000000 × 7930 miles) ÷ 23.6 miles/gallon = `1.344067797 × 10¹⁰ gallons

1.344067797 × 10¹⁰ gallons = $1.344067797*10^{10}\ gallons *\frac{9.50\ kg}{1\ gallon} =1.276864407*10^{11}\ kg\ of \ carbon\ dioxide$

4 0

3 years ago

How are sublimation in evaporation similar

diamong [38]

Evaporation is when a liquid turns into a gas, while sublimation is when a solid turns into a gas. Both involve absorbing energy to break apart the bonds of the substance. On the other hand, an example of sublimation is dry ice.

3 0

3 years ago

Read 2 more answers