Question

The midpoint of DG is M(-1,5). One endpoint is D(1,4). Find the

Answer 1

Answer:

G(-3, 6)

Step-by-step explanation:

$midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )$

Substitute the coordinates of M and D into the formula:

$( - 1,5) = ( \frac{x1 + 1}{2} , \frac{y1 + 4}{2} ) \\- 1=\frac{x1 + 1}{2}& ,&5&= \frac{y1 + 4}{2} & \\ - 1(2)= x1 + 1&, & 5(2) &= y1 + 4 &\\ - 2= x1 + 1&, &10 &= y1 + 4 &\\ x1= - 2 - 1&,& y1 &= 10 - 4 &\\ x1= - 3&, &y1& =6 \: \: \: \: \: \: \: \: \: \: &$

Thus, the coordinates of G is (-3,6).